<p>guys i didn’t get why the diagonals are 9 , i put it 3 , if it was 9 it will b joining 2 vertecies of adjacent sides</p>
<p>what about the one which gave x y and z as lengths of a triangle? then asked which statement cannot be true</p>
<p>i got x<y-z or something like that :/</p>
<p>0 is divisible by 3…</p>
<p>1000 - (999/3) = 667</p>
<p>@wholegrain was that choice e or a?</p>
<p>JP, numbers LESS than 1000.
I was kinda surprised to see the mark of the beast on my paper. :c</p>
<p>Sides of a triangle X, Y, Z</p>
<p>Triangle Inequality Theorem: </p>
<p>X + Y > Z
X - Y < Z</p>
<p>Y + Z > X
Y - X < X</p>
<p>X + Z > Y
X - Z < Y</p>
<p>Thus, out of the choices given, the answer was X > Z + Y</p>
<p>guys i didn’t get why the diagonals are 9 , i put it 3 , if it was 9 it will b joining 2 vertecies of adjacent sides</p>
<p>it was choice A</p>
<p>Equilateral triangle base is 10, so the height of the triangle must be 5 rad 3, 50 rad 3/2 was the area of the triangle multiply by 8 was 200 rad 3</p>
<p>was there a question with answer 3 rad2 to it?</p>
<p>what was the question in the triangle with x, y, z?</p>
<p>^fianchetto, I am wondering the same thing. Can somebody retell the question for that problem</p>
<p>Can someone explain why 62x^2 is right. I got it right out of complete luck.</p>
<p>@ rich, im not sure but
wasnt b c d
the same choice that
one length was smaller than the sum of two lenth and
a and e one length was greater or less than the difference of two lenths</p>
<p>There are 1000 numbers less than 1000…if you include 0</p>
<p>0 is divisible by 3…</p>
<p>1000 - (999/3) = 667</p>
<p>@ widly
it was 2x,3x,5x
2x3x2
3x5x2
5x2x2
is 12+30+20 which is 62</p>
<p>JP, positive integers.</p>
<p>^JP it says POSITIVE integers… 0 is not positive</p>
<p>richardt92: You must be forgetting something</p>
<p>9 = <a href=“http://i947.■■■■■■■■■■■■■■■/albums/ad319/quailroost/hexagon.jpg[/url]”>http://i947.■■■■■■■■■■■■■■■/albums/ad319/quailroost/hexagon.jpg</a></p>
<p>what the hell are nonadjacent sides, i put 9 but what are nonadjacent sides.</p>
<p>curse u SAT!!!</p>