<p>think about this</p>
<p>adjacent vertices do not have a vertex between them.</p>
<p>9.</p>
<p>Hey guys I was wondering. Does anybody remember if UTS was Choice E, because I may have gotten the easiest question wrong because I bubbled it in wrong. Anybody remember the choices for that? And was the exact question U>T>S or S<T<U</p>
<p>Hey was just wondering if anyone remembers if C was the correct answer for the parabola question with a,b, and k. Not sure if I got that right, can’t remember what option C was, so hoping for some help here.</p>
<p>is that question real or experimental?</p>
<p>I think it was E (2k-a)</p>
<p>yes the answer was e.) uts but i dont remember the exact question</p>
<p>The distance quesstion?I just vaguely remember it was a parabola…</p>
<p>Does anyone remember a problem where all the answers were the absolute value of x-k is less than or greater than c (where c and k are both different constants in the answers) and the question was something like a<x<b?</p>
<p>you made my day!!! thx</p>
<p>what about uts? i don’t remember coming across that question.</p>
<p>It was a simple question, but i thought i had it wrong. On Sunday i was checking the ‘official’ October math section on here and saw the answer as UTS. The problem was like s<t<u. make the biggest number and obv its UTS, but i could have sworn i had put STU, however i was 100% sure i put E. so i was just wondering whether or not the answer UTS (the real answer) was E. Confusing? Sorry lol</p>
<p>I think UTS was E.</p>
<p>UTS was E, yes</p>
<p>lol thank you so much guys or gals!!! I stress out so much sometimes, but everyone that replied Im so happy that I would pay one million dollars to each person as a reward sadly I dont have that much money sorry haha thx again!</p>
<p>hey guys for that one question with the three circles. I, II and III. </p>
<p>I heard the answer was 6/7…how? i remember putting 6/11…i forget what the question asked for does anyone remember? Didnt it say II has half radius of I and, III has 1/3 radius of I …find the _______? confuzzled :/</p>
<p>@harvardbound: the solution is simple. if you were to plug in 6/7, you’d realize that the radius of the other 2 circles wld be 3/7 (half the first circle) and 2/7 (a third of the first circle). the total areas must add up to 1—> (6/7)^2 + (3/7)^2 + (2/7) ^2 = 1.</p>
<p>was the question asking for the total areas to add up to 1? i think i read it wrong. ■■■. lol. was 6/11 even a choice?</p>
<p>It said that the sum of the three areas was pi, meaning you could just divide that equation by pi and get (r1)^2 + (r2)^2 + (r3)^2 = 1</p>
<p>Yes, 6/11 was a choice, but it’s wrong. I saw someone make the same mistake earlier on the thread by converting the fractions into decimals and adding them up, but he/she forgot to square them, so it was wrong.</p>
<p>So I had the blue cover test that went essay,r eading, equating (math), math (grid-ins), etc</p>
<p>So can someone refresh my memory as to which questions were on the equating section?</p>