October 2009 SAT Math

Test Preparation SAT Preparation
761

<p>it was experimental. i think you are referring to the computer screen background/picture question. the right answer was 120.</p>

762

<p>If I have about 3 wrong answers (1 wrong in grid), then the score will be … ?</p>

763

<p>That probably translates into a 740 I think. Last November I also got exactly 3 MC questions and 1 grid-in one wrong, and got 740. Don’t know how harsh the curve for this Oct test is gonna be though.</p>

764

<p>the answer was 666. i bet lots of 800ers got tricked by the “less than 1000” in the question and put 667.</p>

765

<p>hey does any one remembet the questions baout the diagonal in the hexagon i answered 9 but my friends are tellin me that there was condition and that the answer was 3 does anyone remember the qeustion exactly?</p>

766

<p>It was nine.</p>

<p><a href=“http://i947.■■■■■■■■■■■■■■■/albums/ad319/quailroost/hexagon.jpg[/url]”>http://i947.■■■■■■■■■■■■■■■/albums/ad319/quailroost/hexagon.jpg&lt;/a&gt;&lt;/p&gt;

767

<p>Thnx,South KP! Oh>.<heck no=“”>.< I did so carefully on that experimental one>.<but I was interrupted by the supervisor’s asking to see my passport+not having enough concentration during the second 25-min math section~~oops,too bad!
Hope I would be fine!K…I shall let it go then…</heck></p>

768

<p>but wasn’t there a condition saying that diagonals not joining 2 adjacet sides??</p>

769

<p>Two vertices on the same side. </p>

<p>But there’s a very simple way: Every diagonal goes through 2 vertices(pl. of vertex). From every vertex you can draw 3 lines. And you have 6 vertices. So: 3x6/2=9</p>

770

<p>thx and another question i had an experimental math section can someone tell me the answer of the last question of the 16 backgrouds and 8 pictures was it 112 or 120 ?</p>

771

<p>Yes, it is.</p>

772

<p>It was 120. 16x8-8=120</p>

773

<p>was that question experimental???</p>

774

<p>if you did not have it, then probably :-)</p>

775

<p>but if it were verticies on the same side when we join them we get the side itself so the conditon then makes no sence , i think the answer is 3</p>

776

<p>try to draw them. There are 6 vertices, so from every one of them you could draw 5 lines. 2 of them are NOT diagonlas, which leaves out 3 diagonals from each of them.</p>

<p>Please, stop trying to convince us, I’m sorry but you’re simply wrong.</p>

777

<p>ok im just the discussing the condition that was given , the way u said makes no sense a 2 verticies of the same line make the line itslef , the question said a line joining 2 verticies of non adjacent sidesssss</p>

778

<p>dude there was no condition… the question just defined what a diagonal was and asked you to find how many there were… sorry</p>

779

<p>im sure there was the word adjacent</p>

780

<p>And thats why I said to divide it by two. Got it?</p>