<p>@UsernameInvalid/@chloeee: the test was terrible. (Agree)</p>
<p>I was debating periodicity, but I’m pretty sure I bubbled the wrong choice :(</p>
<p>@UsernameInvalid/@chloeee: the test was terrible. (Agree)</p>
<p>I was debating periodicity, but I’m pretty sure I bubbled the wrong choice :(</p>
<p>I think n >1 because the correct answer was P odd and >3</p>
<p>What’s a score worth cancelling if I’m looking at top tier schools? :/</p>
<p>I’m pretty sure it just said n>1, I don’t remember a >orequal sign there.</p>
<p>If you think of the two people as being on a number line, the person 4 km south of the post office would be at -4, the person 2 km north would be at +2. </p>
<p>Their positions on the number line t hours later would be -4+10t and 2+5t.</p>
<p>So the difference in their positions (=distance between them) would be abs val((2+5t)-(-4+10t))=abs val(6-5t)=abs val(5t-6). </p>
<p>At t=0, this gives absval(-6)=6, confirming what’s given: one’s 4 km south, the other 2 km north.</p>
<p>For 0<t<6 5,=“” abs=“” val(5t-6)=“” is=“” decreasing=“” (they’re=“” getting=“” closer=“” to=“” each=“” other),=“” however,=“” at=“” t=“2/5” ==“” 0.4,=“” the=“” person=“” south=“” of=“” post=“” office,=“” gets=“” post-office=“” and=“” presumably=“” stops=“” moving=“” 10=“” km=“” h,=“” so=“” for=“”>0.4, the problem is meaningless.</t<6></p>
<p>Plugging in each answer choice would just confirm that the higher the value of t, the smaller the distance.</p>
<p>Hope this helps.</p>
<p>@AforAmbition anything under 730-740 will look bad.</p>
<p>@Hiking7610 can you check my method a few pages up…why would that be inaccurate
Also, the question didn’t specify that the person stops at the post office</p>
<p>@Hiking, plus the person who’s 2 km away is heading east, not north :/</p>
<p>guysssssssss
I skipped 3 and I know I got at least 1 wrong. 800 still a possibility?</p>
<p>i got .24 or whatever for the post office one
2 for the period
p is odd</p>
<p>What was the answer to the 5 letters 5 numbers one? Argh</p>
<p>Also, if I get 800 the next time around, would it not look as good if I didn’t do so well on my first try? I omitted 4 and I’m pretty sure I got no more than 5 wrong, maybe got 3 wrong? Not sure…</p>
<p>to: chloeee </p>
<p>In your method, you used what looks like the pythagorean theorem. Was the person 2 km away from the post office east/west of the post office (creating a 90 degree angle and therefore making pyth. theorem applicable)? I thought the person was 2 km north…</p>
<p>The person was 2 km east and the other was 4 km south, so it would be a right triangle</p>
<p>@AforAmbition, there are 5 choices for letters and 10 choices for numbers, and since ur choosing 5 of each,</p>
<h1>choices for letters = 5 * 4 * 3 * 2 * 1 = 5!</h1>
<h1>choices for numbers = 10 * 9 * 8 * 7 * 6 = 10! / 5!</h1>
<p>total = 5! * 10! / 5!</p>
<p>TO: AforAmbition </p>
<p>5! * 10!/5!</p>
<p>Thanks, AforAmbition–I clearly misread the problem</p>
<p>chloeee: you were right :)</p>
<p>Ahhhh how are you guys feeling? I’m debating whether or not I should cancel. This test was definitely unexpectedly hard… The first half was a breeze (finished it in 15 minutes and I was like wow I’m usually short on time!) then I hit the hard questions and…it was not pretty.</p>
<p>Yeah it was harder than expected. I kept with normal pacing (and didn’t speed through the first 30 or so like I should have) and was faced with crunchtime come to the end.</p>
<p>yeahh it was pretty hard to finish. if i left 13 blank and got 2 wrong, do you think I can get over a 700?</p>