<p>to: michael2013 </p>
<p>in polar coordinates, although (1, 120) is not equal to (1, 300), what you can say is that (-1, 120) = (1, 300) and (1, 120) = (-1, 300)</p>
<p>For the post office question, now that you see that the distance is 3.86km isn’t it obvious that the answer ~.26 is right?<br>
It’s not .4 because [f(.26) = 3.86 ]< [f(.4) = 4] and it asked when they would be closest to each other.</p>
<p>My D left 5 out and thinks she got 4 wrong, can some kind soul please approximate score/</p>
<p>Does anyone know the answer to the period question and the # of absolute value solutions question? So far I’m at 2 skip and the trapezoid question wrong ( i thought the height was 2.5)</p>
<p>Mindy: ~720-750</p>
<p>@BioGen, the absolute value solutions was none because an absolute value can’t equal something negative.</p>
<p>The post office question had one person 4 km away moving at 10 km/hr towards the post office; another person was 2 km away moving at 5 km/hr away from the post office.
the distance between them at any given time is given by
((4-10x)^2+(2+5x)^2=d^2, with x being the time in hours and d being distance…
plugging in, the smallest time listed would have the smallest distance between them…
so the answer was .2 something?</p>
<p>Can you get in trouble for posting on here?</p>
<p>Sent from my SAMSUNG-SGH-I997 using CC App</p>
<p>chloee: Agree with the Post office being .2 something. I plugged everything in. It was decreasing from .4 to .2something and then back up again, thus answering the question.</p>
<p>period question was at pos integers it’s 1/2 neg integers it’s -1/2 or something like that so the period is 2 since it’s like a cos graph</p>
<p>the one with what is P was P is odd and >3</p>
<p>thanks that is good enogh not to cancel!</p>
<p>Are you sure about the P question:
It was something like
P+(1+P)^(1+(-1)^((p-1)/1))
Can someone confirm? I don’t think the above one is right, but I do remember that at Even Numbers the exponent was 0, and at even numbers it was P. P was positive.
Which means that P is always odd, and not matter what you do P is P (I think?)</p>
<p>p was always odd and there was another condition that made p > 3…I don’t remember what</p>
<p>Okay, I put some sort of condition as well, but do you remember if the choices were mostly odd or mostly even. I remember that there was only one answer choice that was not with the majority.</p>
<p>Don’t pretend like that wasn’t hard. I left two blank, and that’s after finishing each barrons practice test in fourty-five minutes with an 800. Meh. I hope they curve this like a boss</p>
<p>For the periodicity one, how can you have a periodic function when the function isn’t even a curve? It was just points that were not connected, because everything between them weren’t integers and therefore were not applicable to the function. I put (E).</p>
<p>@UsernameInvalid, the test was terrible…
@WhartonKid, a periodic function repeats its values at certain intervals and the interval for this one was 2</p>
<p>I thought that up to 38 everything was easy and fair game… after that I freaked out and only answered two in the 40’s.</p>
<p>For the p is odd one…did the question say n was greater than one…or n was greater than or equal to 1?</p>