<p>What was the answer to the question asking what p was?
The answer choiced were someing like:
p is odd
p is odd and greater than 3
p is even
p is even and less than or equal to 2…</p>
<p>odd, your answer choices dont seem correct, pretty sure there was only one odd</p>
<p>@hiking
“The polar equivalent of (1/2, -root(3)/2) is (1, 5pi/3), which I think was the only one in quadrant IV anyway.” </p>
<p>Wasnt it 1, 2pi/3 because the angle was 120 wasnt it. Because tanx = -root 3, so x = -60 = 300 = 120. Im pretty sure 300 in radian form wasnt given, so it was 120, or 2/3 pi.</p>
<p>Also for the linear regression, I think i got 200. Because I thought the pattern was mutiply by 10 and subtract 10, was it not? And the number was 21? I dont really remember the details of the question.</p>
<p>for the p one, I put p is always odd, no domain restriction
which one has 1 and -2 as zeroes: I only
which function has values always greater than or equal to 0: I and II (only one that didn’t fit was tan^2(x)-1 or something like that</p>
<p>@michael2013: 300 in radian form was given, it was choice E.
linear regression: I put it in my calculator, formula was y = -0.513 + 9.058x, plug in 21 and you get 190</p>
<p>Ditto at P is odd.</p>
<p>Going through this discussion, I feel like I may not even have taken the same test as everyone here. It’s almost all vanished from my head!</p>
<p>i got p is odd</p>
<p>@hellohelloo, dammit for the linear regression one, was 200 an answer choice?</p>
<p>^i believe so. for the one with 1 and -2 for zeroes does anyone remember them? idk y but i feel like i might have put I and II,</p>
<p>i took it for the 1st time, so let me ask this:</p>
<p>if you say you borought a TI and that you are in AP Cal will they lower you points or what?</p>
<p>colllegebound, i think 1 was defnitely it, i dont remember which one the other one was though. i remember one of them canceled out the zero. so i think you may be right. i know it was either 1 and 3 or 1 and 2</p>
<p>"“The polar equivalent of (1/2, -root(3)/2) is (1, 5pi/3), which I think was the only one in quadrant IV anyway.” </p>
<p>Wasnt it 1, 2pi/3 because the angle was 120 wasnt it. Because tanx = -root 3, so x = -60 = 300 = 120. Im pretty sure 300 in radian form wasnt given, so it was 120, or 2/3 pi."</p>
<p>I got (1, 5pi/3) too because it was 60 degrees clockwise from the x axis, which means 2pi-pi/3… right?</p>
<p>And did we ever come to a conclusion about the period one? Sorry maybe I missed it going through the pages…</p>
<p>dammit, well based on the feedback, I think I might get a 780 or 790.</p>
<p>Gah, I think I might cancel the score and just take it again because isnt anything lower than an 800 bad because of the curve? I remember I saw the MIT avg for SAT II Math was 800… Should I cancel the score?</p>
<p>My d left out 5 and thinks she got 4 wrong, will she be above 700, approx. what score?</p>
<p>also, just to make sure, in polar coordinates,<br>
1, 60 is not equal to 1, 300 even though the tangents of 60 and 300 are equal? So there is no such thing as an equivalent positive angle when doing polar coordinates (if you know what i mean)?</p>
<p>If I left 13 blank and got 2 wrong, do you thing I can get over 700??</p>
<p>@Nspired, I was definitely one of the choices, but II had asymptotes at 1 and -2. III only had 1 as a zero, because (x-2) was present in the numerator and denominator, so it cancelled out. I think only I was the answer for that one.</p>
<p>hellohellooo now that you say that i think i put that. w.e it didn’t occur to me as a question that i would get wrong. </p>
<p>yeah now that you mention it. i remember one had one zero and not the other. and one just didn’t have any at all.</p>
<p>what is the consensus on the period one? iput none for that one. </p>
<p>for me i got the period one wrong, trapezoid one, and value over 5…cant believe i just put .1 when i saw it… god dam.</p>
<p>also whats the consensus on the post office one? the question was that one kid is moving north towards the office at 10 km/h, and he’s 4 km away. the other kid is 2 km away and moving away at 5 km/h. find the time when they’re closest to each other…if you chose 0.4 hours then they are 4 km away from each other but 0.24 hours, they’re 3.68ish km away from each other</p>