<p>Yes, in the question it talks about equilibrium. The “k” is talking about it the Keq, I believe. A catalyst will not affect the Keq, but it will affect the “k”, or rate constant. I’m not sure if the Barron’s topic you’re looking at is talk about rates. The answer choice is pretty vague.</p>
<p>Ahh okay thank you! So now I just need to remember that the rate constant is catalyst and temperature dependent and Keq is dependent only on temperature. And is it Mg? I have this system where if the huge increase in ionization energy occurs between, say, group 2 and group 3, the element will be in group 2</p>
<p>Are the answers Mg, ligand exchange and methyl orange?</p>
<p>from the 2012 ap exam, question 6, can someone explain why the metal is copper and how you find the answer to part b? our class hasn’t even done electrochem yet…</p>
<p>You are very correct, thelemonisinplay!</p>
<p>@diddly You use the standar cell equation Ecell=Ereduced + Eoxidized (also seen as Ecell= Ereduced - Ereduction of the oxidized…use whichever…just a preference…I like the first.) the give you the E of the cell which is .47. The E of the anode is .13 v. 47v - .13v = .34v, which is the E of Cu.</p>
<p>ohhhh okay, that makes so much more sense, thank you! just one more thing, though (sorry!!!). how do you know that the Eanode is .13? thank you!!!</p>
<p>No, no, you’re fine! This is what this thread is for!</p>
<p>You know the Eanode is .13 because Pb2+ + 2 e- -> Pb(s) is .13v.</p>
<p>got it! thank you so much, honestly. i’m actually starting to get electrochem! :D</p>
<p>Yay, thanks Niquii77! Do we get formula charts on this exam? Also, are we allowed to use calculators for both parts or just on free response?</p>
<p>Calculators are only allowed on Part A of the free response question. I think we’re given the formula packet for the entire exam because the packet included the periodic table.</p>
<p>^^ and that’s why I need to review some old-fashioned multiplication and long-divison LOL</p>
<p>Oh, snap. Are you serious? We’ve never practiced any free-response without calculators in our chemistry class…</p>
<p>Lol, you should have your teacher start taking away the calculators. Questions 1-3 (55 minutes) are calculator. Questions 4-6 (40 minutes) are without calculators. In my class we go on schedules. We’ve been taking two or three tests a week for the last two weeks and will continue up to the test. Are you guys being timed?</p>
<p>No, not really… Sort of. The tests are timed, but not like the AP. And we’ve never had non-calculator free response.</p>
<p>Come on guys, just a week left. Let’s revive this thread!</p>
<p>*Who is credited with the discovery of the neutron?
(A) Millikan
(B) Rutherford
(C) Chadwick
(D) Marsden
(E) Geiger </p>
<p>Under which of the following sets of circumstances will the pressure of a gas DEFINITELY increase?
(A) Raising the T and reducing the V
(B) Raising the T and increasing the V
(C) Lowering T and reducing the V
(D) Increasing n and increasing the V
(E) Decreasing n and increasing the T</p>
<p>The standard enthalpy of combustion of Hydrogen gas requires how many moles of Oxygen gas?
(A) 0
(B) 1
(C) 2
(D) 0.5
(E) 1.5*</p>
<p>Wow! It has been a long time!</p>
<p>(C) Chadwick
(A) Raising the T and reducing the V
(B) 1
?</p>
<p>How is prep going for you guys? I still haven’t really started because I’ve been focusing more on biology… I’m screwed, ugh. This is why I shouldn’t have taken 7 AP classes.</p>
<p>You got everything except the last one.
1H2 + 0.5O2 → 1H2O</p>
<p>I haven’t been doing any outside preparation. I’ll do fine on the exam so I’m not worried. I only took 3 APs this year! :D</p>
<p>Oh lolz, I forgot to reduce the coefficients. I had 2, 1, and 2. Ah well.
Dang, I wish I felt as confident about it as you - As you know, our teacher kind of sucks because he’s new to this and taught us a lot of stuff wrong… The only thing I know for sure 100% is electrochem. The rest is kind of ehhh. According to appass, I’m going to make a 4… I need more questions! Lol.</p>