<p>*What shape would you expect the complex ion [Co(NH3)6]2+ to be?
(A) Octahedral
(B) Tetrahedral
(C) Square Planar
(D) Linear
(E) T-Shaped</p>
<p>What are the expected products of the following reaction?
[Ni(NH3)4]2+ + H+ ==>
(A) Ni
(B) Ni + NH4+
(C) Ni2+ + NH4+
(D) Ni2+ + NH3
(E) NH3 + Ni</p>
<p>Which of the following would you expect to act as a ligand in a transition metal complex?
(A) Water
(B) Ammonia
(C) Chloride ions
(D) Fluoride ions
(E) All of the above*</p>
<p>I’m not really good at explaining complex ions. My class spent a day on this. There’s a list of common ligands that you should be able to find online. Memorize them. It’ll be extremely helpful. Looking at this problem OH- and Al jump out at me. These two will form the complex ion. [Al(OH)6]3- I’m not sure if the charges are correct. There is usually more than one way to a complex ion. The safe numbers to go with are 2,4, and 6. Just make sure the charges add up in the end.</p>
<p>If this was a question 4, your final equation would be:
Al+3 + 6OH- → [Al(OH)6]3-</p>
<p>Dear god, I’m completely hopeless at complex ions. We never even covered that. I’m going to take a wild guess at these three.
(A) Octahedral
(C) Ni2+ + NH4+
(D) Fluoride ions</p>
<p>What shape would you expect the complex ion [Co(NH3)6]2+ to be?
<a href=“A”>b</a> Octahedral<a href=“B”>/b</a> Tetrahedral
(C) Square Planar
(D) Linear
(E) T-Shaped</p>
<p>Octohedral is correct because there are six bonds.</p>
<p>What are the expected products of the following reaction?
[Ni(NH3)4]2+ + H+ ==>
(A) Ni
(B) Ni + NH4+
<a href=“C”>b</a> Ni2+ + NH4+<a href=“D”>/b</a> Ni2+ + NH3
(E) NH3 + Ni</p>
<p>NH3 attatches to H+ leaving Ni2+.
Which of the following would you expect to act as a ligand in a transition metal complex?
(A) Water
(B) Ammonia
(C) Chloride ions
(D) Fluoride ions
<a href=“E”>b</a> All of the above**</p>
<p>All of these choices are ligands.</p>
<p>I didn’t even realize all three of these questions involved complex ions! Whoops!</p>
<p>Haha, that’s no problem. Hmm, why do I always seem to be getting the questions you give me right, but when I take a chemistry practice test, I’ll probably get only half the multiple choice right? (I haven’t done a practice test yet, I’m so screwed omg)</p>
<p>Haha, thanks. Maybe I do, but I just feel like I don’t know enough to do well. Definitely not enough for a 5. It just frustrates me; if I had a better teacher, no doubt I would be confident in my ability to make a 5.</p>
<p>@thelemonisinplay, do you realize you only need to get about 50 right out of 75 and do decently on the free response to get a 5? just practice using real collegeboard questions and I guarantee your score will go up. with AP chem, it’s not so much knowing the material, it’s knowing how to apply it and how to test well with chemistry, and that all comes from practice, fortunately! just to show you, i finished the barron’s book today and attempted a free response and bombed it, but I have been doing more since then and I have been doing MUCH better. stay positive! :D</p>
<p>how are you guys studying for question 4? im good with the easy double-replacement reactions and solubility rules but I always get so confused when they throw in ‘acidified solutions’ or react two compounds with the same element in each</p>
<p>Is the curve really that generous? I’m not sure how the free response questions are scored/weighted so I’ve been assuming that I’ll get maybe 4 out of 9 points and 5 out of 10 points. Why are the different free response questions worth different amounts of points? There’s one worth 15, one worth 8, and one worth 10, but 3 are worth 9…
For acidified solutions (I’m assuming you’re talking about net ionic reactions here), you pretty much have to memorize what the products would be. Cr2O7 + H+ → Cr3+ + H2O and MnO4 + H+ → Mn3+ + H2O.</p>
<p>okay thanks guys :))
to answer diddly’s question and add onto thelemonisinplay’s explanation, you do have to memorize what species are produced for a complex redox reaction.</p>
<p>my teacher gave us a nice chart of the common oxidizing and reducing agents. it’s not too bad. </p>
<p>Sorry, yes - I meant MnO4- went to Mn2+ not Mn3+. Not sure why I didn’t catch that mistake before. @taffys - That’s a great review sheet! OMG I wish I had one of those. I need something that summarizes/lays everything out nice and neat for me. The notes our teacher gave us are riddled with errors and are hard to go through.</p>
<p>Do you mean the Cracking the AP Chemistry exam Princeton Review book? Everyone’s been recommending it. I’ve had my copy for months but never even cracked it open once I guess I’ll start today then…</p>
<p>omg taffys that’s an amazing sheet, thank you!!! that whole thing makes sense now lol. i’m also thinking of reviewing our class labs cause they seem to ask ALOT about that, and there’s a guaranteed frq about labs. And i studied barron’s but it’s waaaay too much to go over in a week so im just gonna read through 5 steps to a 5</p>
Maybe I do, but I just feel like I don’t know enough to do well. Definitely not enough for a 5. It just frustrates me; if I had a better teacher, no doubt I would be confident in my ability to make a 5.</p>
I guess I’ll start today then…</p>![http://i1333.■■■■■■■■■■■■■■■/albums/w624/taffier/IMAG1861_zps9d330bc1.jpg[/url]](http://i1333.photobucket.com/albums/w624/taffier/IMAG1861_zps9d330bc1.jpg%5B/url%5D){kind=link}
