<p>Yeah, there was a large triangle with two lines drawn on it that separated it into three smaller triangles. Two of those triangles were said to be isosceles, and you were given a vertex angle of 40 degrees on the right triangle and a base angle of 40 degrees on the left triangle.Then you were asked to find the value of x, the angle separating the two triangles. The value was 180-(70 + 40) = 70 degrees.</p>
<p>as shown in the link, the curve depends on difficulty. As a person who blew the math i wish i get good curve too, but guys come on math wasn’t hard. since there were some logic questions that made a lot of people fail we can hope about the good curve, but personally i dont think thats gonna happen sighhhhhhhhhhhhhh</p>
<p>Does anyone remember the question with a circle and a tangent line on the left side of the circle? There were a few angles listed already in the problem. Does anyone remember the answer? </p>
<p>I think some of the answers were 55,60,65,70,75 :p. If I recall correctly, it was #15 on Section 2 for those who had math experimental</p>
<p>Math:
(-1,3)
3 ordered pairs
x+y=6
9/22
cube=54
x=5
slope = -2/7
whale= ⅛
sum of something = -3
165 minutes
median-avg = 0
ratio of markers to reststops = 2:1
|w-500|less than/equal to 30
max perimeter = 33
don’t remember question, but 48
temperature approximation = 130
another question, 330
grid in function = 9/6
halfsquare = 128
diagonal of square = rad130 about 11.4
length AC = 2xrad3
volume cone = 12pi
number of line segments to connect points = 6
y = 65 degrees
roman numeral question = I,II, and III
greatest value = a+b
250 seniors
y^2-x = 0
f(4)=g(4) — 4
2B8/11, remainder = 7</p>
<p>If anyone remembers anything else, please add to this!</p>
<p>guys for the absent question I got a 1420. As I recall it said that 8 students were absent two days of the week and 1 student was absent 3 days of the week. Also, 5%of the total students at the high school = # of students absent 1 day. So I added up the absences and subtracted (8<em>2) and (1</em>3) because those were the students absent for more than 1 day and we have to find # of students absent 1 day only. I got like 71—> 71/.05 = 1420!</p>
<p>And for the trail marker one, I also had like 5 minutes left over on this section and recall their being a marker at the beginning but NOT a rest area. Rest areas are every 6 miles it said, therefore the answer should be 8:3</p>
<p>yes, it seems to me the consensus is 1600 although I’m not really sure why, but I’m positive that the trail one was 8:3. that question makes the difference between a -2 and -3. Is there a chance that a -3 will get me a 750 or higher on this test?</p>
<p>@coolpillow - thats what i think too… im thinking 2 versions of some questions…
i know they are making the SATs really secure now … from cheating/identity</p>
<p>either way there seems to be problems with the trail one being either 8:3 or 2:1
and the entire senior class problem 150 or 250</p>
<p>@studyingforsat - -3 is a 750 if the test has no curves.</p>