Rice Baylor MCAT

Hello!

I was wondering what the MCAT requirement for the Rice/Baylor Program BS/MD is? I have contacted both Rice & Baylor and both have stated that they don’t know. It said that the Baylor 2 Baylor requirement is 501+, but Rice and Baylor’s admissions office did not know what is was for the Rice/Baylor program. If they set it at a very high number then I might not want to apply.

I am legacy to Rice, do research at Baylor College of Medicine, & have an amazing LoR from a Baylor College of Medicine professor (haven’t read it but she is really nice and said she would write an amazing LoR), so I really want to apply, but really don’t want to be limited/ stressed out because of a really hard test that I have to score really highly on.

If anyone knows what it was in previous years or knows it right now please let me know so I can get a ball park. I know the average for the BCM is 517.5 overall, but don’t know what it is for Rice/ Baylor.

I know I will be able to get the 501 since it is the 46 percentile, but I heard that at one point it was a 38 (old MCAT) which is the 99+ percentile and I can’t do that.

bump

I dont currently see a specific requirement for Rice/Baylor.

It is a very competitive program with only 5 or 6 seats. So not sure it is something you need to worry about at this stage before turning in your app. If you are applying for BS/MD programs, you apply broadly, interview where you are invited, and then decide whether a program has tough or easy requirements that you can meet when admitted. There is legacy to Rice but not Rice Baylor and Rice/Baylor is actually one of the toughest programs to get into and there are easier ways to get into Baylor than Rice Baylor. There is usually a large contingent of Rice students who get into Baylor without having gone through this program.

Baylor admit stats for GPA and MCAT have been going up steadily. So getting into Baylor without a high MCAT score might be a moot point whether it is Rice/Baylor or undergrad at college X and applying to Baylor.