SAT January 2012 - Math

<p>Proportional doesn’t mean equal.
It just means that p will always be 1/15th of no matter the value of t.</p>

<p>There was a question that had a square inscribed inside a circle, and I believe they wanted you to find the area of the circle.
Was the area of the square given as two or was a side of the square given as two?</p>

<p>area was 2.</p>

<p>@sp1095</p>

<p>area of square was 2 → side √2 → diagonal/radius = 2 → area = pi</p>

<p>@ cyanosaur</p>

<p>i know… but can you explain why you said the answer is p=t?</p>

<p>What did you guys get for the ice cream scoop question? </p>

<p>So far I have 2 wrong on the grid in, and THREE wrong on the mc. What will that most likely turn out to be?</p>

<p>Could anyone explain how you solve the problem where you find a possible side length for a triangle with one side of length 5 and a perimeter of 20?</p>

<p>@ Cynosaur -the area was pi.</p>

<p>@boison “Triangle Inequality Theorem”</p>

<p>The sum of the lengths of any two sides must be greater than or equal to the length of the remaining side.</p>

<p>7, I believe, was the only value that worked.</p>

<p>I got 7 for the triangle thing. It was the only possible choice.</p>

<p>Was 7 b? Was 5 an answer, obviously wrong, but was that A? </p>

<p>To clarify I think the answer was 7 but was that choice b?</p>

<p>Can someone explain the angle of r + s + t question on the free reponse?</p>

<p>Did anyone get a question where it was like x^2(x-3) = a + bx + cx^2 + dx^3 and you had to find a + b + c + d? I left it blank, ran out of time.</p>

<p>@FastNeutrino I don’t remember this one, may have been experimental.</p>

<p>@ 000ooo000ooo000ooo000ooo000ooo000ooo000ooo000ooo000ooo000ooo000ooo000ooo000ooo000ooo000ooo000ooo000ooo000ooo000ooo000ooo000ooo000ooo000ooo000ooo000ooo000ooo000ooo000ooo000ooo000ooo
-I think 7 was b, but not 100% sure.
@cheme pentagon = 540 deg so 540-140-90-90-90=130 deg.</p>

<p>darn.
-2 MC and -1 grid-in… what do you think my math score will be?</p>

<p>@yankeesfanatic Okay, I kind of thought so, but I was really scared that it might not have been. That math section was kind of crazy, especially when compared with the rest of the math so far.</p>

<p>@ Cheme </p>

<p>R + S + T was 130.</p>

<p>if you looked at the figure as a whole, it was composed of three triangles, therefore it was 3 (180), or 540 degrees.</p>

<p>the angles besides R+S+T were the given (140) and the three right triangles (also 3x90). </p>

<p>so 540 - ((140) +270)) = 130.</p>

<p>hope that made sense!</p>

<p>guys, what was the answer to the problem of the six-sided figure with length x width of 10 and 12? it was in the gird in section.</p>

<p>@Roboticsfre4k, it was 44; 10+12+10+12</p>