SAT Math II June Discussion

I got 30 for the n^k one

who got 104 for the area of the triangle, where they give you the three points

which question was180 dividing n^k

wasn’t n^k 6?

I got n^k 6 too!

because dividing would mean 180/n^k right?
can anyone else confirm

yeah, i got 6, cuz 6^2 is 36 and 180/36 is 5

it’s n^k/180, the other way around. Answer’s 30 I believe.

Yea it was n^k/180. 30 was the only answer choice that, when exponentiated, is always divisible by 180

Anyone remember what they got for that parametric equation when it asked for the y-intercept? I got -5 by just plugging x=0 on my calculator but the graph looked different. I’m not too familiar with parametrics, all I know how to do is how to put them into my calc lol

I also got 30 for the n^k question btw

@mpurd18 If I remember the question correctly, it was -1/3

@indabasszone ah, it looked like that was it but I was unsure, thanks.

The area of the triangle with the three points given is 136.5

I omitted two. The n^k one, and the two-way radio one (with route 1 and the girl’s house)

Anyone have an idea of the curve? I’ve only taken Barron’s practice tests so I don’t know how this one’s difficulty compares to other real tests.

Was the slope of parametric equation

-7/3

for the f(g(x)) one where f(x) = cos2 x and g(x) = sin x, how can you simply say that the answer was 1 - x2? This implies that the system is a set of parametric equations, but you are really solving for composition. So I got stumped when I plugged in g(x) into f(x) and got (cos(sinx))2. How do you solve this?

cos^2 btw sorry

@physicsgod981 Not sure what you mean by the whole parametric thing…if f(x) = 1-x^2, then f(g(x)) = 1-(sinx)^2, which is equivalent to (cosx)^2 because (sinx)^2 + (cosx)^2 = 1