<p>I didn’t think Hampton made sense. It was tricky, but then I thought like a weasel. Did that sentence have anything at ALL to do with what Hampton was about? Nope. It’s one of those overthinkers.</p>
<p>And yeah it was 11.2</p>
<p>I was forced to guess on that one, but I did the question once I got home and the correct answer is 11.2. Co-linear would mean that the vertical lines decrease by .8 each time, so for the final trapezoid, the height is 4.0 (you have to picture the trapezoid sideways), base 1 is 2.4, and base 2 is 3.2. So if you do the formula for an area of a trapezoid .5h(b1+b2), you get 11.2
Unfortunately, I had a brain fart and couldn’t figure this one out.</p>
<p>lol i guess on 11.2</p>
<p>what was the answer to the math question which had a triangle inscribed in a rectangle. it asked for the area of the triangle, i believe. the only answers that made sense were either 12 or 18.</p>
<p>Does anyone know what I’m talking about?</p>
<p>Also, what was the Hampton question again?</p>
<p>What was the answer to the question that asked about acquainted, befriended? (English Section)</p>
<p>^^ I wasn’t to sure on that one, I figured the answer was acquainted, since the rest had to do with becoming friends, and an acquantince is not a friend, and does anyone know when we get our scores?</p>
<p>kellian, I remember that one, I think the answer was 18</p>
<p>needfortofu27, I put “acquainted” as the answer. I dont think “acquainted so-and-so” is the right use of the word, it should be “became acquainted with so-and-so”</p>
<p>haha, dang, I guessed 12 on that one.</p>
<p>Can anyone else confirm what the area of that triangle inscribed in the rectangle?</p>
<p>ilmayday - do you remember the specifics of the question at all? that one really frustrated me, and I would like to figure it out.</p>
<p>@kellian do u mean the angles?</p>
<p>no, i’m talking about the triangle inscribed in the rectangle. it asked for the area of the triangle. I think the answer was either 12 or 18.</p>
<p>kellian,
so there was the triangle inside the rectangle, and the top length of the rectangle had points A, B and C in a line. the top of the triangle was at point B, and the length of the rectangle was 18. it said line AB was 1/3 of line AC. AC = 18 so AB = 6 and BC = 12. then it said the width was 1/2 AB, which is 3. so to find the area of the triangle, you do 1/2 (BC) (width) = was 1/2 x 12 x 3 = 18</p>
<p>sorry if thats confusing, cant explain it very well</p>
<p>for the last part of the science,
does anyone remember the answer to:</p>
<ol>
<li><p>the allusion to environmental pressure</p></li>
<li><p>the second to last question i think, the answers were:
hypothesis 1 and 2
hypothesis 2 and 3
hypothesis 1, 2, and 3
none</p></li>
<li><p>the last one with the chart</p></li>
</ol>
<p>Basically, [url=<a href=“http://dl.dropbox.com/u/457347/triangle%20in%20rectangle.jpg]this[/url”>http://dl.dropbox.com/u/457347/triangle%20in%20rectangle.jpg]this[/url</a>] for the “triangle in rectangle” one.</p>
![http://dl.dropbox.com/u/457347/triangle%20in%20rectangle.jpg]this[/url](http://dl.dropbox.com/u/457347/triangle%20in%20rectangle.jpg%5Dthis%5B/url){kind=link}
<p>@littlestar</p>
<ol>
<li>That one asked which of the hypotheses supported the idea that a resistance trait formed as a result of T1 being introduced into the E.coli population. Both Hypothesis 1 and 2 supported that. Hypothesis 3 said that such a gene must have existed before the introduction of T1.</li>
</ol>
<p>So, a second shot at explaining [url=<a href=“http://dl.dropbox.com/u/457347/act%20math%20problem.jpg]this[/url”>http://dl.dropbox.com/u/457347/act%20math%20problem.jpg]this[/url</a>] one, anybody? Proportionally, i.e. visually, h seems to be about 21, but I haven’t figured out a practical way of figuring that out.</p>
![http://dl.dropbox.com/u/457347/act%20math%20problem.jpg]this[/url](http://dl.dropbox.com/u/457347/act%20math%20problem.jpg%5Dthis%5B/url){kind=link}
<p>Thanks a lot, ilmayday!</p>
<p>Even though I got it wrong, it feels good to know how to do it.</p>
<p>littlestar - I kinda forget those, sorry.</p>
<p>thanks for the pic</p>
<p>ya, for some reason I thought ab was one third of bc instead of ac.</p>
<p>stupid mistakes plague me</p>
<p>^ i think someone explained this earlier
but if you assigned coordinate points to each point on the triangles
you can find the linear equation of each of the diagonals
then you find the intersecting point of the equations by setting them equal to each other
thus, the y value of the intersecting point is the height</p>
<p>@littlestar</p>
<p>Oh yeah, I overlooked that post. That was a pretty good way to do it.</p>
<p>does anyone know when we get our scores in the mail? and do they even go online?</p>