<p>i hope so that’s what i put … .
Hey SAT200 i saw you in us history thread …haha</p>
<p>@sat200
yup
what were the answer choices for the interval shaft error with 75?</p>
<p>What was the answer for "if x is an integer, which of the following would not give you an integer?</p>
<p>all the answer choices were polynomials over monomials, and stuff like that…</p>
<p>so anyone know for sure what the june 2010 curve was?</p>
<p>and the perimeter was 15 right? cuz the june 2010 link says like 29.7</p>
<p>@swedish… I thought it was the first option… x/(x-1) is never an integer if x>2 (they gave that condition in the problem). unless I’m completely blanking here</p>
<p>@tryingtoohard 15 was the eq but 29.7 was the triangle inside the cube with sides root of 98</p>
<p>I did horribly, but apparently, the consensus seems to be that it was easier than normal.</p>
<p>I’m so confused. I’ve done AP Cal, I’m quite decent at math…I don’t know what happened.</p>
<p>I think the test was hard, a couple of complicated problems</p>
<p>@rdly2ttg yeah same! i was hoping for an 800 but now i think i got about a 750. i’m pretty sure i got a 5 on my calc exam too</p>
<p>^^^ @rdly2ttg – You’re in the same boat as me, man. Took calc, yet I’m going to do badly on this – maybe around 740-770. Thank god I’m nearly positive I aced us hist.</p>
<p>"I did horribly, but apparently, the consensus seems to be that it was easier than normal.</p>
<p>I’m so confused. I’ve done AP Cal, I’m quite decent at math…I don’t know what happened."</p>
<p>You don’t even know how ironic this is to read. I consider myself to be good at math, and I aced AB calc as one of the top students in my class. Yet, this turned out terribly for me.</p>
<p>okay, does anyone remember what the symmetry question was asking?</p>
<p>It gave two pints (2,2) and (-2,-2) and asked what they were symmetric about. The answer was y=-x and the origin. Anyone know the answer to the one that asked which of these cant be an integer if x>2?</p>
<p>x/(x-1)
I tried the others and they all yielded integers
Besides you can never get an integer with that equation</p>
<p>aced AB calc?</p>
<p>but what about BC calc? <em>trollface</em></p>
<ol>
<li>f(3) - f(1) = 6 </li>
<li>Segment with five distinct points: 10</li>
<li>Last problem (disk/laser): B) 987</li>
<li>Complex number: 2-3i is also a root</li>
<li>Given x=√(2+√2), find (x^2-2)^2: 2</li>
<li>Angle with slopes of line l and m (2/5 and 3/5): 9.16 degrees</li>
<li>Parametric: -1/3</li>
<li>Infinite series: 2 - (1/n)</li>
<li>f(t)=2cost and g(t)=sin(t/2), find the slope of the line connecting (0, f(0)) and (pi,g(pi)): -1/pi</li>
<li>Value of x^x as x approaches 0: 1</li>
<li>Domain, range: {1, 2, 3} </li>
<li>ln x = e^-x: 0.27</li>
<li>Average speed of car: less than 50 mph</li>
<li>Graph shift, f(x) = f(x-2) + 3: two to the right, three up</li>
<li>Graph of f(x) = 1/g(x): 3</li>
<li>(a^3)^2=123.1: 2.2</li>
<li>Extending line segment, with ratio 1:2: (8, 12)</li>
<li>Perimeter of equilateral triangle: 15</li>
<li>Unit circle/chord: 2sin(theta)</li>
<li>Perimeter of triangle on a cube with side length 7: 29.7</li>
<li>Inverse graph: D)</li>
<li>Absolute value: b</li>
<li>Volume of cone: 18.88</li>
<li>Logic (if…, then…) t >= 3</li>
<li>Period: sin(2pi)</li>
<li>Average scores/min. number of judges: 5</li>
<li>1.5 radians → degrees: 85.9</li>
<li>5^(2x+1) = 96: take log of both sides and solve => 0.918</li>
<li>Point symmetry: I and III (about origin; across y=-x)</li>
<li>n(n+1)(n+2): divisible by 2 and 3, but not 4 </li>
<li>Perpendicular product: -1</li>
<li>x+x+x = x^2 : 0,3</li>
<li>sin (thetha) = x^2, what is sin (2theta): 2x^2 root (1-x^4)</li>
<li>1. f(3) - f(1) = 6 </li>
<li>a(10)=155</li>
<li>girls and boys 2(g-10)</li>
<li>1/32</li>
<li>12 is the number that makes the expression composite, not prime</li>
</ol>
<p>That’s not true @Kili16.</p>
<p>2/(2-1) is 2. That’s an integer.</p>
<p>Is there a complete list of all 50 answers because I think the thread from 2010 only has 35 of them?</p>
<p>
</p>
<p>The directions sad x > 2</p>
<p>What was the hardest problem for you guys</p>
<p>The condition was that x was greater than two. it couldnt be equal to two.</p>