USA June 2011 SAT: MATHEMATICS Discussion Thread

<p>@cin I had experimental reading and didn’t see that problem so you probably had exp math.</p>

<p>I’m probably wrong but multiples of three would be implied that there would be 66, so you need one that would fit in 100 three times,so wouldn’t it be a number between 26 and 33?</p>

<p>I know it was experimental. I just want to know how to answer questions like that for October.</p>

<p>can anyone confirm that 16 works for the 63 integers problem?</p>

<p>@Brotherjames: There are 33 multiples of 3. 100-33 = 67. Since you need there to be 63, you need something that will take out 4 more numbers, not counting repeats. A lot of different numbers work. 20 works, for example:
20, 40, 60, 80, 100. Since 60 is already taken out by the 3, that leaves you with 4 numbers.</p>

<p>@jetfan: 20 works. See above.</p>

<p>Does anyone remember how you did the 10% question? I somehow got 18.8 (which rounded to 20%)…</p>

<p>@super that’s what I did too. i think someone mentioned something about them already giving you the cumulative values.</p>

<p>@superninja: That was the one I got wrong. I think the trick was the numbers on the right of the graph were cumulative, not per month.</p>

<p>@neonblue</p>

<p>so 33 wouldnt work :(</p>

<p>16 works</p>

<p>Its what i put, and i literally wrote every number out. 1-100. </p>

<p>It works.</p>

<p>16, 32, 48, 64, 80, 96 are multiples of 16 between 1 and 100.
48 and 96 were already removed by the 3, so that leaves you with 4 more removed. Add that to the 33 also removed and you get 37 removed, or 63 integers remaining, so yes, 16 works also.</p>

<p>Here are the Grid-In Answers I got
5.5
42
4
9
65
1600
15
180
10/3
17</p>

<p>@Brotherjames: no, nothing divisible by 3 would work, because all its multiples would have already been removed by the 3, still leaving you with 67 remaining. Sorry :(</p>

<p>Also got -(x-some number)^2+(-2)^2 for question 8 in the grid in math section</p>

<p>@ goodscorer
The question asked about the addition of two sides of a triangle being twice greater than the other side. If you do 6,4,5 triangle and figure out what the angle for 6 is it’ll be 90 degrees. There are scenarios where it doesn’t have to be an equilateral triangle. Therefore the answer was a which was none</p>

<p>@kunalkunal2</p>

<p>6, 4, 5 does not work because:</p>

<p>–> 4+5=9 which is not equal to 6X2=12</p>

<p>@sat12345
i got all the answers you have except the last one.</p>

<p>@SAT12345: *Also got -(x-some number)^2+(-2)^2 for question 8 in the grid in math section *</p>

<p>That was the right answer. It was same as A but with an extra + 4 added.</p>

<p>The rest had +(c)^odd# which makes a negative.</p>

<p>So i agree. B. -(x-2)^2 + (-2)^2 was right</p>

<p>Does anyone know if 5.5 was an answer on the grid-ins? And was 3.33 the answer to the first grid in on one of the sections?</p>

<p>6+4 = 10 which is 2 times greater as 5…</p>