<p>@howgoesit12: Your math is correct, but the equation y = x^2 + anything is a parabola opening upward. The only way the parabola would open downward is if there is a negative constant for the x^2 term.</p>
<p>@Fyodor: The hypotenuse is ten, but if you use (8-x) and (6-x) you are subtracting out x too many times. The equation would be 10=(8-x)+(6-x)+x. (Hypotenuse=segment without overlapping + segment without overlapping + segment that overlaps.) This leads to x=4, which is the correct answer.</p>
<p>@Sprinter, hopefully that explains it well enough?</p>
<p>Ronaldo: Were the numbers 20, 70, x, and 270?
You have three different distances with an average of 120 ft. The formula for average is
sum/number of items=avg Since there are three distances, the total distance is 3*120 = 360.
Then you just find the differences between the *distances.
(270-x)+(x-70)+(x-20)=360
leads to x=180 ft.</p>
<p>@neonblue: on the 20, 70, and 270 one, I got a different answer.</p>
<p>Average distance is 120. This means 20+70+270+x=480. 20+70+270=360.
480-360=120=x.</p>
<p>I said the answer was 120. Maybe I remembered/read the question wrong? Maybe you did?</p>
<p>@raza68 Nah. I think it was experimental. The question was like this:
if P Triangle M=M and P Square M=P, which of the following equations must be true? It was super strange.</p>
<p>@MarioKartExpert</p>
<p>The question said average distance from the unknown point is 120</p>
<p>That means (x-20)+(x-70)+(270-x)
all divided by 3
=120</p>
<p>The answer is 180</p>
<p>Shoot, I guess I read the question wrong. </p>
<p>Also, you all seem to have gotten your hands on the answers. Do you remember and realize or something?</p>
<p>If anyone still cares, I left parabola question in my calculator:
-(x+2)^2+(-2)^2 (this one has the highest - vertex @ -2,4)
-(x+2)^2+(-2) (second highest - vertex at -2,-2)
-x^2+2 (vertex at 0,2)</p>
<p>why is the question with the average pencil thing 1.6?</p>
<p>Yes, we just remember. I came on here as soon as I left the test… I don’t usually remember questions until someone mentions them, and then I remember how I solved it.</p>
<p>@lolhello: Each kid has 3 writing utensils. If 1.4 of them are pens, then 3-1.4=1.6 have to be pencils. (Think about it as if it were one kid in the class - realistically impossible but conceptually easier to see.)</p>
<p>does anyone know which section was the experimental??</p>
<p>@IchigoK: I’ve seen at least three different experimental sections (three different people with questions nobody else recognized). Something about Crazy Hats, driving chairs back and forth, computer background and toolbar colors, a pyramid with a smaller pyramid and comparing the volumes, etc. Any of those sound familiar?</p>
<p>which question had 42 as an answer?</p>
<p>@lolhello</p>
<p>Each student had either 1 pen and 2 pencils or 2 pens and 1 pencil. If the average number of pens each student had was 1.4, what is the average of number of pencils?</p>
<p>Let’s say there were ten students. Thirty writing utensils in all. You could say that 30-number of pens=number of pencils. This means 30-14=16. Divide all of these numbers by ten to get 3-1.4=1.6. Hope this helps!</p>
<p>anyone guess what -4, all mc, would be?</p>
<p>I thought the question with 1’s and 2’s said that the twos had ones in between them?</p>
<p>@collegeboundman:</p>
<p>Five twos and five 1s form a ten digit number. All of the twos were in a row. How many ways could you make the ten digit number?</p>
<p>2222211111
1222221111
1122222111
1112222211
1111222221
1111122222</p>
<p>The answer is six times.</p>
<p>Does anyone know the answer for the g(-1) question? I put D…I think that was 5?</p>
<p>Damn guess I misread.</p>
<p>Any chance a -3 would be a 740?</p>
<p>An average curve would give a 720, a very generous one 740. Unless those are all grid-in questions. Then yes you should get a 740.</p>
<p>What do you think -1 or -2 will be? I think I got the rope with the girls wrong(misread the question), and I’m not sure about the I II III question with the triangles, I answered II only, “they must be equilateral.” I was debating between that or “None,” as I was confused with the wording of the question. If “ANY” two sides add to get twice the third side, is that equilateral? I was thinking of an isosceles triangle then.</p>
<p>It’s equilateral. ANY implies that you could pick ANY two sides and it would work - NOT hey this one specific set of sides works, but not the others. Think of it as someone giving you a triangle and you get to pick ANY two sides you want. What that actually means is that it must work with each set of sides.
It doesn’t matter which set of sides you pick, it will always work.</p>
<p>Sorry, I’m new to the whole curve guessing things. I don’t know the inner workings of the SAT. I just work the problems as best I can.</p>