USA June 2011 SAT: MATHEMATICS Discussion Thread

<p>@decresendo - 700ish </p>

<p>im pretty sure the answer to that was 40?</p>

<p>does 17 work for the last grid-in question as well?</p>

<p>I am a bit confused on the parabola one where t=x-b and y=(-t)^2</p>

<p>I originally thought it would be the parabola that opens up. However, let’s try a value of 2 for b, so we are substituting (x-2) into the second equation.</p>

<p>That gives us (-x+2) because t is negative. (-x+2)^2=(x^2 - 4x +4). The parabola that opened upward was still on the x axis and hadn’t been moved up or down. However, squaing t would always move the parabola up or down, so I chose the parabola that opened downward as it was the only viable choice. Does this make sense?</p>

<p>

</p>

<p>Oops. I know there was one with 5x5 cubes and that the answer was forty (or something like that). Sorry if I was wrong.</p>

<p>If I get a 690 again… :frowning:
I really want to get at least a 700. :)</p>

<p>@howgoesit12… i picked a constant for B, twice, and it showed a parabola facing upward that was moved along the x-axis, and I believe that was a consensus for that question.</p>

<p>GRID INS:
11/2 (2x+4 = 7, what is x+4)
65 ( z/4.5 = 24/12 = x/4 = y/24. what is x + y + z?)
4 (k+n = kn)
42 (can someone remind me what the question for this was?)
1600 (there were 560 juniors and u wanted to find the entire student body pop)
9 (idr the question)
15 (idr the question)
10/3 (graph asks what (y, 5) is. given numbers indicate that the slope is 2/3, so you then plug #s it into y=mx+b where b=0)
19, 20, 16, 14 (63 numbers remaining when multiples are 3 are removed from all numbers 1 to 100 inclusive)
180 (rope question. average distance from x to each of three other people)</p>

<p>MULTIPLE CHOICE:
1.6 (average number of pencils)
-(x+2)^2+(-2)^2 (max value problem)
4 (intersecting circles with a 6, 8, 10 triangle. what is RS?)
10% (cumulative percent employed in april).
4, 25, 50, 100 (subset that has factors of 100 but not the multiples of four)
-1 (20th term when the first time is -1)
40 boxes (how many 5x5 cubes in the figure)
6 possible ways (5 2’s and 5 1’s. how many numbers if all 2’s have to be next to eachother)
96 (10% january price increase in a $100 coat is then discounted 10% in february).
Only II; equilateral triangle (triangle is constructed so that any two sides added together equals double the third side)
2:1 (ratio question. whats the ratio of the accepted to the rejected?)
5 (three pictures of one cube. what does the side with a 1 face?)
parabola opens up (choice D) ((-t)^2 question)
105 degrees (find trapazoid angle x)
m=2k
16 (square root of two squared question)
4, 12 (find coordinates of vertex P)
g(x) = 4, -6 (what is |f(x)|)
70< x < 165
5pi/2 (diameter is 10pi, sector is 90 degrees. what is the arc length)
area of triangle = 25 (base is 5, height is 10)
50% (what percent of x is 50x/100?)</p>

<p>@levinel Thanks.</p>

<p>Also- did anyone else have a math section with a crazy P Triangle M question?</p>

<p>@howgoesit12- which one? I remember one with 2 triangles and u have to find X. Is that the one u r talking about?</p>

<p>Anyone care to guess was -2MC, -1 grid in would be?</p>

<p>Made stupid mistakes. x.x</p>

<p>■■■. On that one grid-in question involving the slope, I think I used 3/2 as the slope rather than 2/3 because I wasn’t paying attention and got a completely different answer. :frowning: </p>

<p>That’s -1 so far…</p>

<p>@ undeniiable- I thought this math was really easy(maybe normal?)… taking that into account, I would guess about 740</p>

<p>@wannabeactuary:
It is two. The hypotenuse has to be 10. the segments that form it are (8-x) and (6-x). Adding them together would get x=2, no?</p>

<p>By the way, could anyone explain how to solve the question involving the average distances one person was from three others on a rope or something? I literally guessed and checked on the test and actually came up with 180 (yay for intuition :)).</p>

<p>asdfghjkl; man. okay, thanks.</p>

<p>This may have been experimental. There were two overlapping circles with a right triangle somewhere in between. One circle had a radius of 6 and the other had a radius of 8; so the hypotenuse of the triangle was ten. The question asked what was the length of a specific portion of the hypotenuse (I think it was segment RS). </p>

<p>Does anyone remember the answer?</p>

<p>4 for certain Sprinter</p>

<p>@sprinter246-4 was the answer</p>

<p>ya 20 would work</p>

<p>i have a question about that grid in integer question…would 19 also work?</p>

<p>nvm…saw the eariler post</p>

<p>I got two wrong, stupid mistake on the april 10% question, and I think the one with the parabola (thought it was x > etc…</p>

<p>What would my score be with these two wrong?</p>

<p>Also, what would it be with only one wrong.</p>

<p>Thanks in advance for the estimate!</p>