<p>it was between 5 and 6 i believe</p>
<p>Wasn't it 13/12, so it was between 6 and 7?</p>
<p>Yeah, I just remember that when I did it I got like 6.5 or something.</p>
<p>it was not exactly 13/12 it was different number i think</p>
<p>oh no i don't remember what i did for that one...i had no idea how to do it. i think i just put A which might have been like between 0 and 1...but im sure it's not right</p>
<p>And sorry, I don't remember what number it was..</p>
<p>Hey guys, is it like basically impossible to get a 35 if you make some silly mistakes?</p>
<p>We should make a list of all the answers we know so far! So then we can kind of figure out how many we got wrong out of how many have been discussed, and how many we haven't discussed, and stuff.</p>
<p>i put between 6 and 7</p>
<p>ya! that sounds like a good idea!</p>
<p>on my calculator i just did 5^(13/12) and it came out as 5.7172....
so i think it may have been between 5 and 6 if that was a choice unless i'm doing something wrong</p>
<p>what was the supermarket percent increase question asking about specifically?like what was the word?i dont remember...abravesone i think that the height of the cylinder was 6 and the radius was 5.im not positive though.that could be a different question</p>
<p>okay so people are saying the last question on the math test had an answer of 2sqrt3.
How is this so? i dont remember if the question asked for radius or diameter,but...</p>
<p>The way i percieved this is that the length of the sides of the cube were 4. If you draw in a diagonal, it would form a 45 45 90 triangle. The length of that diagonal would therefore be 4sqrt2, which would also be the diameter. if the diameter is 4sqrt2, then wouldnt the radius be 2sqrt2?</p>
<p>Maybe it was ^13/5 or something. I really don't remember. Are you sure it was 13/12?</p>
<p>marcr92 i think that's wrong.log base 5 of 5^13/12 is just 13/12 because i think that the log base 5 and the other 5 cancel each other out or something, leaving you with 13/12.that's how i did it</p>
<p>If the height was 6 and the radius was 5, then yeah the answer should have been 150pi.</p>
<p>maybe it was a different number.because 13/12 is like 1.08 or something, which doesn't make sense.i know i put 6 to 7</p>
<p>i dont remember what I said for the cyllinder.i didn't know that i was supposed to have that formula memorized so i just guessed.i think i guessed 150pi or 180pi</p>
<p>it must've been a different number...i remember the 5's canceled out..
so whatever exponent they gave you was the only thing you needed, and it was definitely between 6 and 7..
it might've been 13/2?</p>
<p>150pi and 180 pi were not two choices
there was only one of them, so if you guessed and you think you guessed 150 or 180, you got it right</p>
<p>The problem is, I don't remember the exact values for the log base one. But I'm pretty sure, like 85% sure that the answer was "between 6 and 7."</p>
<p>Vaultipod, you're taking the diagonal of the square, which is not necessarily the radius of the sphere. What I did was, I found the diagonal of the square first, which was 2rad2, and then to find the radius of the sphere, I used the pythagorean theorem. I can't really explain it that well, but I got 2rad3 too.</p>
<p>My friend also told me that there's this formula for finding the diagonal of the CUBE, which, divided by 2, should be the radius of the sphere. It's: the square root of ( lengthsq + widthsq + heightsq).</p>
<p>If you do it using that formula, itd be the sq root of ( 48 ) which is 4rad3. Then you divide this by 2, like I already mentioned, and you end up with 2rad3.</p>