<p>It's definitely 1/24.</p>
<p>There are 4 events that can be arranged in any order. 4 factorial = 24 is the number of possible arrangements of these events.</p>
<p>Only one of these 24 arrangements is the true arrangement (leaving 1 and 6 as is).</p>
<p>1/24 here.</p>
<p>The TONE WAS CONTEMPLATIVE</p>
<p>yeah i agree, i don't think it was mournful...</p>
<p>because the whole time he was contemplating his life without the family he didn't know and his sister as a baby or whatever.</p>
<p>Well. I think I'm going to do worse than last year.
I completely guessed on the Redwood passage of the reading, and the Last Chemistry topic of the Science. </p>
<p>And my goal was a 32. :|</p>
<p>Was that test not harder than the ones in the past? Especially the math. I completely forgot all of the equations for conics...</p>
<p>lol i forgot conics equations too... all you have to do is plug (x,y) into each equation, and see which one comes out to make both sides equal...</p>
<p>which problem was that for?</p>
<p>it was the like...2'nd or third to last one on the math section where you had to find the equation for the figure on the graph...</p>
<p>the answer to it was E i believe.</p>
<p>the ellipse? it had denominators of 4 and 9 equaling 1 right?</p>
<p>yeah that one. sorry, i couldn't remember exact numbers.</p>
<p>I got contemplative also.</p>
<p>idk what I put...i guessedon my scantron</p>
<p>What was the answer to how many sets of xy solve</p>
<p>xy=3 and i dont remember the other one but i think i did it wrong because i solved for (x+y)^2 and now that i think about it i think they were seperate ahh damn</p>
<p>what did the exact question say SISIS cuz I don't remember that...</p>
<p>oh SISIS that was a hard question i thought...</p>
<p>i couldn't find any solutions b/c i was pressed for time.</p>
<p>crazy what was the question.......and where about of the 60 questions was it? towards the end ?</p>
<p>i believe it was towards the end... and it was like how many (it might of said real, not sure though) numbers are solutions for both equations xy=3 and (x+y)^2=10 ? I'm not positive if that's accurate, but that's what i remember.</p>
<p>yeah i also put no solutions because</p>
<p>I was under testing time so somteimes u dont think clearly but if it was</p>
<p>(x+y)^2=10 then it is 0 solutions correct but if it is </p>
<p>x^2 + y^2=10 it is 4 does anyone remember which one it was</p>
<p>and the problem was how many sets of x,y exist to solve both</p>
<p>xy=3 and (x+y)^2=10 (((or x^2 +y^2= 10 ,, i dont remmebr which it was :(</p>
<p>Oh now I remember..yah I got stumped on that question and tried plugging in so many different #'s but couldn't come up with any solutions...I might've put 0 or guessed randomly...i remember crossing out "infinitely many" and staring down 0 so I hope I put 0.</p>
<p>yeah me too... i couldn't find a solution at all, and i crossed out infinitely many.... and i just ended up putting no solutions, hopefully that is right.</p>