<p>yeah but i had it like that in both the reactants and the products</p>
<p>MC--easy easy easy! (no i'm not cheesy--just happy [although i skipped some])
FR--Easy and hard</p>
<p>overall: 3 or 4</p>
<p>Is the AP test over internationally? If not, we really shouldn't talk about "what was on the test". It is definitely violating the rules and furthermore, not fair for everybody.
I don't want my grades to be canceled!! And I'm sure none of you guys will want that either. So could we please stop talking about what was on the test???</p>
<p>riny ur a looser hahaha</p>
<p>i so owned that Free Response. MC was harder, but i still got like at least 50 rite</p>
<p>one of my friends got the first part wrong to the last question and therefore all his other answeres were off.. </p>
<p>im so glad i did 7.</p>
<p>gah I messed up 7..only one i missed more than 1-2 pts on :(..probably missed 5.</p>
<p>Your friend is fine, because they take points off for the incorrect response, then do not take off any more if he consistently and correctly applies it for the remaining responses.</p>
<p>ziggy, how so? I'm sure you did fine with just one bad free response.</p>
<p>Yeah, I missed 15 pts tops on FR I think (probably more like 10)...just worried about the curve I guess</p>
<p>haha for that Keq question (#2) i finally figured out why i got k = 0 (lol) i subtracted at the end, instead of dividing</p>
<p>yea dumb mistake but it was only one math error so hopefully i will only lose 1 point (rather than messing big time somewhere else...like i was worrying about)</p>
<p>which question was this?</p>
<p>example of the ridiculous ease of this test...</p>
<p>Simple lab procedure to find the difference between Na2CO3 and CaCO3?</p>
<p>hmmmm
well
put them in water
stir
and see which dissolves</p>
<p>derp</p>
<p>It was the last subquestion for frq #2. It was on thermochem. I got some huge number for Keq, like something x 10^45?</p>
<p>Didnt the question state that both were solutions, though?</p>
<p>^Yea I remember seeing something that threw me off from using a lab test with solubility.</p>
<ol>
<li>No. It said you had two solid samples.</li>
<li>You can't have an aqeous solution of CaCO3. That's the point.</li>
</ol>
<p>Edit: I'm sure there is a way to force CaCO3 into solution (changing temp, pressure), but you cannot simply drop it into water and stir and make it dissolve.</p>
<p>I said that you could put both into a solution of NaCl, since in that double replacement reaction only one is soluble. Is that still feasible? Your way is definitely right on.</p>
<p>I'm not 100% on this, but I think that this would happen:</p>
<p>When you put Na2CO3 into the NaCl solution, both salts would be present in solution in full dissociated form and no reaction would take place. If you put CaCO3 into the NaCl solution, the CaCO3 would not dissociate and I don't think a reaction would happen, either. So yeah, you'd be able to tell the difference, but the NaCl would serve no purpose.</p>
<p>AH, I just checked, solids in other aqueous solutions will dissolve. Phew.</p>
<p>for the Na2CO3 and CaCO3 question I couldn't remember the solubility rules so I just said heat until 1 melts, thats CaCO3, lol. Cause the bigger molecule and weaker lattice energy, hopefully that one works, because it technically is correct.</p>