<p>Oh then you are right....</p>
<p>watd u guys get for the the question where it asks if the freezing point was lower if you had aqueous NaCl or just plain water?</p>
<p>How about the oxidation-reaction reaction that asks you which one is oxidized? Pb(s)+PbSO4^-2+something else--->CuSo4+...</p>
<p>It's a volumetric pipette designed to hold one volume only, and the other end makes sure you don't get air bubbles. I'm sure that is the answer.</p>
<p>Freezing point is lower with aq NaCl</p>
<p>Pb is oxidized</p>
<ol>
<li>freezing point is lower for aq NaCl but the second wasnt a correct explanation</li>
<li>Pb was oxidized</li>
</ol>
<p>[url=<a href="http://www.chem.yorku.ca/courses/chem1000/equipment/pipette.html%5DPipettes%5B/url">http://www.chem.yorku.ca/courses/chem1000/equipment/pipette.html]Pipettes[/url</a>]
^^pipettes, specifically of the <em>volumetric</em> sort</p>
<p>That is true. Freezing point is lower for Nacl.</p>
<p>Lead is oxidizided.</p>
<p>ah, excellent</p>
<p>Anyone get the problem with a 22.4 container that has both oxygen and hydrogen? There are 16g of oxygen and they ask you how many moles of hydrogen is there?</p>
<p>0.5 moles....i think</p>
<p>I had .5 moles of H. Here is my reasoning. There are 22.4L total, at STP this means there is 1 mol of total gas. Since there were 16g, which equals .5 mol, of O2 there must be .5 moles of H.</p>
<p>I distinctly remember that question saying that an aqueous NaCl solution has a HIGHER freezing point than distilled water. So that should be false</p>
<p>What about the neutralization reaction, which one was that? Anyone remember?</p>
<p>that'd be H3O+OH=H20</p>
<p>great! thanks, thats what i put</p>
<p>I think that was H30+ + OH- --> H20</p>
<p>0.5 moles definitley.</p>
<p>how about for the one where you have to find the density of a solid. It shows two pictures of the water level int he flask and it tells you the mass of substance. it was weird because the answer was either 0.5 or 0.50. same thing right?</p>
<p>^ it was either 3.0 or 3.00. I put 3.0</p>
<p>nah, sig figs. i think it was two you needed?</p>
<p>i think i said the one with less significant figures...</p>