June 2009 ACT Math Discussion

<p>What was the determinant question again? I remember:</p>

<p>det = ad - bc
—> a b c d
det [ x -8, x x] = -16</p>

<p>It asked for what value of x would be to make the determinant work.
In this problem, the answer was -4, but everyone is saying it is 4. Did I remember it wrong?</p>

<p>The correct problem was:
x 8
x x</p>

<p>(4x4)-(4x8)
16 - 32 = -16</p>

<p>not:
x -8
x x
(-4x-4)-(-4x-8)
16 - 32 =-16</p>

<p>PS: its ADCB :)</p>

<p>@tbonus</p>

<p>Why do u say it’s ADCB? I thought there was a consensus that C was clockwise?</p>

<p>I put ADCB but I think it’s ACDB now.</p>

<p>And what was the question for the one with “1:3”</p>

<p>the 1:3 question was about the shaded region vs. the non-shaded region. It was a rectangle with triangles in it.</p>

<p>the parallelagram with the triangles in it was 1 unshaded:3shaded</p>

<p>B was counter, C was counter, D was clockwise
im pretty sure, the “counterclockwise” for c was on two lines with a hyphen, or something, for some reason it was easy to skip the word counter (if i remember correctly)</p>

<p>what was answer to very first question on test?</p>

<p>I also put ADCB.</p>

<p>@tbonus</p>

<p>Do you happen to remember if 4 was the first answer or the last answer on the determinant problem?</p>

<p>i cant remember it might have been C?</p>

<p>All I remember is that a tried the first answer which was -4 or 4, it didn’t work, so I tried the last answer which was -4 or 4 and it worked.</p>

<p>first question? I think I put A.</p>

<p>yea, for the first question, the answer was like 20V + 10P or something like that.</p>

<p>Does anybody remember the exact question for the one that asked to find “m”</p>

<p>I got -6 and I can explain it if i have the right equation etc.</p>

<p>it was something like 9-3m+n=0 or something…</p>

<p>The possible answers were: </p>

<p>a) 3
b)-3
c) 6
d)-6
e) 9</p>

<p>i thought this was going okay but i ran out of time and had to guess on the last 5!</p>

<p>Yeah I ran out of time as well. I ended up not filling in the bubbles until I got to the reading section, and I just bubbled in random letters for the ones I didn’t get to</p>

<p>To KungFuMasta:</p>

<p>The question was something like this…
x^2+mx+n = 0
Both m and n are integers. If the ONLY value possible for X is -3, what is the value of m?</p>

<p>The answer would be three since (x+3)(x+3)
when you factor it out, your m value comes out to be 6</p>

<p>as for the curve on this one, April was u could get 1 wrong and get a 36 and get 3 wrong and get a 35, 4 wrong 34, and 5-6 wrong for a 33…and a lot of people feel this Math section was more difficult, meaning there will more than likely be a very nice curve</p>

<p>@bannas </p>

<p>so is the answer 6 or 3?</p>

<p>@mabsjenbu
I would say the answer is 6. Pretty sure about it. And I think he got 6 too</p>

<p>Yea, answer is 6.</p>

<p>I missed that one then. I only think I missed a few but I just put -3 in for x and assumed n was zero for some reason. -3^2 + -3*m +n=0. I simply put 3 in for m and assumed I was right. Darn.</p>