<p>@ bausser
Draw the line y=-x and plot the point (3,2) on a piece of graph paper.
Then plot the point -3,-2 and connect it to 3,2.
If (-3,-2) is the reflect of point (3,2) over the line y=-x, then the intersecting lines should be perpendicular.</p>
<p>If you reflect something like (a,b) over the line y = x, then you get (b,a), right? so over the line y = -x should be (-b,-a)…
I wish I actually remembered this during the test :[</p>
<p>The period question was 2. You don’t add the periods. If you graph it, you can see that its 2. I don’t think you can determine it from the equation. Also, its definitely (-2,-3). If you fold the paper, it lands on that spot. </p>
<p>Sigh I ommitted 2 and got 3 wrong so far. Hopefully curve is in my favor. Someone told me May is usually harder…</p>
<p>Does anyone remember the exact wording of the flagpole problem? I thought height (y-component) was associated with sin so I put 10sin66… Probably should have worked it out instead of just guessing that. >_<</p>
<p>@JakeBlues: Given f(x/2) = √[( 1 + f(x) ) / 2] and f(a) = 0, what is f(a/4)?</p>
<p>You had to find f(a/2), then plug that back into f(a/4).</p>
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<p>@Aaron2011: We were given distance from P to flagpole as 10 and angle as 66˚. If you let the height be h, you have tan 66˚ = h/10, so h = 10 tan 66˚.</p>
<p>Apparently the May curve last year was crazy. -7 at least. My friend told me his friend omitted 7 and guessed on 6, and still managed to get 800.</p>
<p>Edit: Oh and apparently it was the same test as June 2006.</p>