<p>No, it just said each dot needed to touch each other dot.</p>
<p>I think it’s still 6, not sure though. Any input?</p>
<p>Lol fail I put 4 ;-;</p>
<p>@FullMetalx, the perimeter is 33. @Galinda, that still comes to 6.</p>
<p>Yes, polymath was the answer. I put that and googled it when I got home.</p>
<p>the people that said 4 might not have accounted for the diagonals</p>
<p>its 6:
Dot A joined with Dots B C and D: 3
Dot B joined with dots C and D: 2
Dot C joined with Dot D: 1</p>
<p>i got a 65 as well, so you’re probably right on that question</p>
<p>I said 6 because you can create 3 diagonals for one point, then 2, then 1, and then no diagonals.</p>
<p>@ blaaaargh: ur the biggest dumbass ive ever seen in my life learn how to read holy **** thos 9 people were count 2 times stupid dont ur idiotic insight</p>
<p>look:8 were absent exactly 2 days
1 person 3 days</p>
<p>graph: monday:25
tuesday:20
wednesday:10
thursday:15
friday:20</p>
<p>25+20+9+6+11=71</p>
<p>71/5=x/100
7100=5x
7100/5=1420</p>
<p>@amuftah can you explain?</p>
<p>CR: was the undersea creature one “defy” and “disparity” OR “elucidate” and “discrepancy”
CR: in the ape passage, did Passage 1’s last paragraph :
A) acknowledge that a position might seem unreasonable
B) concede that an opposing argument is convincing
??? with reasons please.</p>
<p>Also, writing: “than that expended traveling” or “that that of traveling” when referencing the rocket going from Earth to the Moon</p>
<p>graph: monday:25
tuesday:20
wednesday:10
thursday:15
friday:20
Monday: 25
Tuesday: 12 (accounting for the 8 out two days and therefore already counted on monday)
Wednesday:9 (accounting for the 1 out three days and therefore already counted on monday)
Thursday: 15
Friday: 20
thats 81 then you set up this proportion: 5/100=81/x
1620 is the correct answer</p>
<p>It is definitely 1600.</p>
<p>Total number of absences (from the bar chart) is 90.
The number of students who missed one day of school is 90 - 8 - 1 = 71.
The number of students who missed AT LEAST one day of school (the number of students the graph represents) is 71 + 8 + 1 = 80.
80 is 5% of 1600.</p>
<p>@Divy1234: That would have worked if you accounted for the second of three days for the person who missed three. You only accounted for them once.</p>
<p>No, there were 90 absences. 71 for 1 absence, 8 for 2 absences each, and 1 for 3 absences, which makes 80 students in total.</p>
<p>80 = 0.05x
x = 1600</p>
<p>my bad remembered the question wrong</p>
<p>you guys are counting an extra person, the one who missed 2 days also missed three days of school. He is part of the group.</p>
<p>@amuftah</p>
<p>Adding up the numbers on the graph, there were 90 total ABSENCES.
8 students were absent exactly twice, and one was absent 3 times.
Each of the 8 is counted twice, and the one is counted 3 times. Thus, subtract the extraneous absence for each of the 8 and 2 absences for the 1.</p>
<p>90-8-2 = 80 total ABSENTEES.</p>
<p>5% of the students were absent at least once, meaning they were ABSENTEES.</p>
<p>.05*t = 80, where t is the total student population.</p>
<p>80/.05 = t = 1600 total students at Jackson.</p>
<p>Can we put this issue to bed and move on?</p>
<p>^It’s 1600, because the one out three days was counted three times.</p>
<p>You only took off one for the three-time-absent guy. Take off one more, so that he’s only counted once: so 81-1 more = 80.</p>
<p>Thus, 1600.</p>
<p>Flamewire is right. I missed that question because I ran out of time. Damn! I knew how to do it, too.</p>