<p>It gave you the graph of a function and you had to shift it 2 units to the right. The question asked for the new y-intercept. The answer was -2 because the original point was at (-2,-2).</p>
<p>y intercept was -2. if you shifted the graph two units to the right, the graph crossed the y axis at (0,-2)</p>
<p>so...realistically, do other people besides geester314 think this test might be -1 is an 800, and why? Is it because people most likely made at least one dumb error because the test seemed to be so easy? Let's hope :-)</p>
<p>Also, for Silvykins (or anyone else that was wondering about the angle problem), I think it was 30 because they told you that AC = CD (or something like that), and based off of that you could conclude the shape was a parallelogram if you connected a line across the top to the other point. From there, you could use alternating interior angles and the fact that the line bisected the angle of the equilateral triangle (60/2) to get 30. </p>
<p>No one seemed to actually say why it was 30, so I thought maybe it would help to put it up. Hopefully, my logic is right :-)</p>
<p>GuitarRckr, I agree with your logic for the 30 degree angle.</p>
<p>i remember that question .. but did it say that it was at point -2 -2 ???? i dont remember seeing that ... and when i moved it two spaces to the right i got -1</p>
<p>No, I'm just saying that there was a point that was at (-2,-2) that became (0,-2) after shifting 2 units to the right.</p>
<p>guitarrckr, that is correct. I used something different though, but I got the same answer</p>
<p>did someone have a question with the other vertex...like (10,4) it could have been experimental</p>
<p>I had that question, could have been experimental since it was one of my 3 25 minute math sections</p>
<p>ok but did you put (10,4)...just to be safe</p>
<p>^
yeah i put that point</p>
<p>I think the (10,4) one was the parallelogram vertex. It wasn't experimental, and it was what I put.</p>
<p>I put 10,4</p>
<p>ditto to ^ and ^^</p>
<p>i don't think it's experimental.</p>
<p>lolcats4, i'm 100% sure it was 10,4, but i have another question.</p>
<p>i have a question about the reflection one. does anyone remember what the actual question was??? </p>
<p>i'm pretty sure there were three lines going across. and only one was labeled like 'l' or 'm' or something. it then asked you to reflect point p across that one line. i think i put b as the answer, but then again i'm not sure (i just drew a line that was perpendicular to the line of reflection)</p>
<p>Was the question "which point could be the 4th point of the parallelogram?" can someone explain 10,4</p>
<p>what was the consensus on the reflections one? I got B, but there seemed to be equal numbers of A's and B's on the thread.
Where even <em>was</em> A on the graph? I don't remember hahaha</p>
<p>I got A, tryptophan
it was two lines, and we had to reflect it twice over the two lines.</p>
<p>For the 4th point,
You had three points and they made the left top, left bottom, and right bottom. you needed the top right, and got the height of the point from the left top, which was 4. the distance between the two bottom ones was 5. so you add 5 to the top left's x, which was (5,4), which makes 10,4.</p>
<p>wow that was a baddd explanation. but hopefully you got the gist!</p>
<p>Well I got Point A and I remember that it was to the left of Point P. I reflected it twice, once across line l, and then across line m (or the other way around, I don't remember).</p>
<p>i'm pretty sure it was just one reflection.....i read the question over many times</p>