the standard deviation with the line passing through the curve was 0?
I got pi-theta also @SlayerWard
Cos was negative and sin was positive so it had to be in the second quadrant
Use the concept of reference angles:
To find a reference angle in the second quad its 180(which is pi)-theta
What was the determinant?
What was the determinant question again?
1-30 were a breeze. But after that is where it got difficult. I was on 32 by the time there was 20 minutes left and I started panicking. I omitted 4 and made educated guesses of 5 to 7 of them. Hopefully I get a 700+
@JoeSmith15 @rogerfedererfan1 the determinant was 0
i got -6… why is it 0?
I entered 0 because I recalled Cramer’s rule for solving equations…
The determinant question was ax-by=2, cx-dy=3 and I think it said that they were parallel so a=c and b=d.
ad-bc–> ab-ba = 0 @rogerfedererfan1
and for the theta one theta was in between 0 and 90 right?
I don’t remember that one, what was it?
it was the one of theta-pi/2… and theo ne which theta is between 0 and 90 and phi between 0 and 180… i think those were the parameters in the question
oh! it was phi = pi-theta right? because -cosphi=costheta and sinphi=sintheta
Last question was 1/8 right?
@katrissRed @werewolf2016 Yeah
Yeah I realize it now. It was pi-theta
I got 16/49 for the integers from 1 to 99 one
I got 2 times because x intercept means y = 0. When you do that you get 2x = x^2 so x can be 0 or 2 which is 2 times intersection
I skipped five and probably missed one, is it still possible for me to get an 800?
@pranav23 that’s what i got too