<p>Wired, you might have to do 3.33. I said 30/9, which is exact. Next time, use fractions so the answer can’t be argued.</p>
<p>Wiredd: 3.3 is, unfortunately, wrong. 3.33 is acceptable as it’s as accurate as you can get. GoodScores: I’m actually not sure if 30/9 is acceptable because while it’s an exact answer, it can be simplified to 10/3, which is what I answered. I don’t know if scantron machines are made to accept answers that aren’t completely simplified. Now I’m curious. Does anyone know for sure?</p>
<p>Based on past curves and the relative difficulty of this test, what would a -1 MC and -2 grid in be? What would a -1 MC and a -1 grid in be? What about just a -1 grid in? These are all raw scores.</p>
<p>@ivyhopeful94
740, 760, 790 respectively.</p>
<p>Thank you!</p>
<p>@syndekit, the question specifically mentioned that (4,4) was the center, however, so it’s irrelevant how they tend to list points</p>
<p>So the correct answer was (4,12) I believe</p>
<p>I wrote in 3.33, but I also wonder if 30/9 would work, I know for sure that both 10/3 and 3.33 are acceptable though</p>
<p>hi all,</p>
<p>do you guys remember the question that talked about the side lengths and the different types of triangles?</p>
<p>i think it said:
if you have a triangle in which adding two sides equal the third side, what MUST the triangle be?
- right triangle
- equilateral
- ONLY two sides equal</p>
<p>i wrote none. because i know that a 3-4-5 triangle has that property, which discredits equi. and only 2 sides. additionally, i also know that equli. triangles have this property, which discredits the right triangle. (since it said MUST.)</p>
<p>lacamotif: I originally said none, but I read the wording of the question again. It said that “ANY” two sides must add up to twice that of the third. Try this: 3+3+(.5)6. This works out to be an equilateral triangle every time. Read the question carefully, for it may trick you. I actually changed to II, the equilateral triangle at the very last second, no joke. “Any” means that you can take any two sides and satisfy the criteria, not just one particular pair of sides.</p>
<p>Sorry man, but that what the SAT does to you.</p>
<p>center of circle as (4,4) with a radius of (-4,4) so (4,12) was the answer i put</p>
<p>how do you find the maximum value?
i put A</p>
<p>The maximum question, it was referring to the vertex. The answer was C.</p>
<p>hm, okay. i actually remember the any part. i interpreted it to mean that it can just be one set of the 2 sides, not all.
idk tho</p>
<p>"My reasoning (which may seem flawed b/c I do not remember the exact wording) was that the center was (-4,4) because CB usually lists points from left to right.
Thus, point a is the center (-4,4) and point b is (4,4),
Making (-12,4) the answer.
Although I could be completely wrong… "</p>
<p>Yeh I got (-12,4) also. I checked my answer for this 3 times. </p>
<p>Although everyone said (4,12), but I don’t even remember that being an answer choice–so I may not be reliable.</p>
<p>everyone who is chipping into the other problems, could you possibly also chip into the triangle question that we are discussion now? (check pg. 46 for specifics.)
what did you guys write?</p>
<p>@loca,</p>
<p>MarioKart is correct. the answer was II equilateral.</p>
<p>It was II: equilateral, because if any two sides are twice the length as the other side, then all the sides have the same length</p>
<p>For the circle question, the center was indeed (4,4) and point B was (-4, 4). It said to pick the coordinates that fit both the center of the circle and a radius from point B to the center which was 8. That makes the diameter 64. The answer (4,12) satisfies it as (4 - 4)^2 + (12 - 4)^2 = 64.</p>
<p>Here’s how I found out the answer was II equilateral. I thought of 2 or 3 scenarios in which the triangle would be true - and the only applicable scenario was an equilateral triangle, in which 2 of the same sides (any two sides) and their sum is always twice the value of the 3rd side. And in the answer choices, there was only one “II” in the choices available. Had the other choices been true also, there would have been at least another option with II in it. but the rest did not have II, therefore, the only possible answer was C, II only. #reasoning lolz</p>
<p>whats this im seeing with an answer being (12, 4) or something? i dont remember anything like that. maybe i just forgot, though…</p>
<p>thatguycolin: There was a question that was as follows:
On an x-y coordinate plane, (4,4) was the center of a circle, and (-4,4) was a point on the circumference of the circle. Which of these points could be on the circumference of the circle?</p>
<p>I don’t remember the choices, but I do know, through reasoning, that the answer must be exactly 8 units away from the center, since the radius is 8, and that all of the choices had integers as points. Here are three possible answers:
(12,4),(4,12), and (4,-4.) I think the answer was (4,12), though I could be wrong. I’m certain I got the question itself right because I found that the other choices, of course, could not be on the circle.</p>