<p>Third choice was square root of sin(x^2) + cos(x^2).</p>
<p>Oh wait, was it (cos^2(2x)+sin^2(2x)) ? Anyways, it won’t make a difference.</p>
<p>If Hiking is right, then that was choice would be correct. But if it was x^2 and NOT sin^2 and cos^2, then it would be wrong.</p>
<p>hkim
If you meant sq rt of (sin^2(x) +cos^2(x)), then it wouldn’t make a difference, but if the arguments were x^2, as you wrote, then it would be false.</p>
<p>Hiking, are you completely sure that you saw it was sin^2 and not x^2?</p>
<p>Wait, for that question, were the answers I and III? I’m getting soooo confused. That’s what I put.</p>
<p>anyone know the minimum raw score for a 700? would 35 be enough?</p>
<p>xquik
Yes, it was sin^2 and cos^2, but whether the arguments were x or 2x, I’m not so sure anymore.</p>
<p>hkim
Yes, I and III</p>
<p>Oh, good. What the arguments are doesn’t matter. And yeah, I put I and III as well.</p>
<p>Wow, sorry everyone. I made typos the whole time LOL. I looked back into the calculator, and I believe it was sin^2(x), what hiking said. Haha, I confused everyone. So it’s not sqrt sin(x^2) + cos(x^2).</p>
<p>FYI: sin(2x)csc(2x) does NOT equal 1 when x is 0 degrees…
sqrt(sin^2(x) + cos^2(x)) DOES equal 1 for ALL values, INCLUDING 0 degrees.</p>
<p>Therefore, I still believe that just III is still the correct answer…</p>
<p>And does anybody remember the choices for the (0,2), (-3,3) problem or if it really had the word “contains”…
Do you remember seeing a (-5,5)??</p>
<p>I think for that question, the range of x had to be from 0 to pi/2, exclusive, but I may be getting confused with another question.</p>
<p>So what are you saying is the right answer?</p>
<p>So I think it’s I and III lol. because you didn’t have to consider plugging in 0 into the equations if there was the condition of x being between 0 and pi/2.</p>
<p>Lol that might actually be what I said I don’t even remember lol
But somebody PLEASE say what the answer choices were for the x^2<4 one…</p>
<p>Also, did it say “Under which of the following intervals is x^2 < 4?” OR did it say “Which of the following intervals contains the solutions of x^2 < 4”
If it’s the first one, (0,2) IS the correct answer.
On the other hand, if it’s the second one, (-3,3) is the correct answer.</p>
<p>Also, if anybody can attest to the fact that (-4,7) and/or (-5,5) were also answer choices, then the question was indeed the first one, making (0,2) the correct answer.</p>
<p>Yeah…we’ve been asking for the answer choices for x^2 < 4 question but no one has been answering. T_____T If I get that wrong, I have 2 skipped and 3 wrong…I hope that’s 800…</p>
<p>I’m 100% sure it said “contains”, because I was really confused about the (0,2) thing until I reread the problem. I know for sure the answer choices included (-3,3), (0,2), and (-1,4). I think there may have been (-4,1) as well. I don’t think there was any other weird choice that included (-2,2) other than (-3,3).</p>
<p>I am pretty sure “contain” was NOT in there. I think it was a typo. and I remember (-4,7) was another answer choice. I had the choices written down around 20 min after the test for that problem.</p>
<p>@Silent: Do you recall it saying ““Under which of the following intervals is x^2 < 4?””</p>