<p>(-4, 7) wasn’t an answer choice.</p>
<p>The answer (-3, 3) is ABSOLUTELY the correct answer. I remember reading this question five times at least and the answer choices at least as many times before answering. I filled in the circle exactly when the test ended. There was no (-4, 7) option since I was really looking meticulously. Before I even read this thread I knew that the question contained the word “contains” and this forum just confirmed this. The people saying that the question didn’t contain “contains” are just sad since they didn’t notice it. I just read through over 20 pages just to say this o.O</p>
<p>And this: I skipped 5 questions and I only know about 2 wrong answers. I probably have a couple more wrong answers, but in the best case scenario I have no more wrong answers and then I have a chance of getting 800! I haven’t even practiced for this and I don’t know the mathematical terms from the test in English, so I had to skip 5 questions. I have never studied matrices, but the other math in the test was pretty basic in my opinion.</p>
<p>Does someone remember which question included matrices?
It could have been among the two I omitted though.</p>
<p>The last question could have been solved with matrices, but it wasn’t necessary.</p>
<p>guys, if you are all so worried about the terminology of the “contained” question, just email collegeboard.</p>
<p>i personally dont remember the question at all- was it an early one? Hopefully I answered it…</p>
<p>What about the question asking how many imaginary roots are in given polynomial of third degree (don’t remember the polynomial)?
I answered there are 2 imaginary roots. Is it correct?</p>
<p>^Yeah, that’s what I got. I double-checked it first by graphing it (crossed only once) and then by using an app that found all the roots. :)</p>
<p>As i recollect, that tricky question was somewhere in middle of the test (i bet that somebody will post here its exact number - guys, how could you remember all of these questions with answers? I was like after a blackout after an exam 
)</p>
<p>
Yeah, just subtract the number of X intercepts from the degree.</p>
<p>I still don’t get the problem about a set or locus of 2 perpendicular lines in the xyz planes, or something like that… I think someone explained it, but I probably skipped a lot through the 24 pages lol.</p>
<p>u guys think a raw of 44 will be an 800?</p>
<p>There was one question about the number of perpendicular lines going through a fixed point on a given line in the xyz plane; the answer to that was “infinitely many”. Another question was something about the locus of points that are equidistant from two intersecting lines; the answer to that was “two perpendicular lines”.</p>
<p>For a complete proof of the perpendicular line question:</p>
<p>Construct two distinct, intersecting lines (make it an x for the proof’s purposes)
WLOG, construct horizontal and vertical angle bisectors
WLOG, construct a line segment perpendicular to the angle bisector on the upper half plane formed by the horizontal bisector.
We now have an upside-down isosceles triangle with a line that is both an angle bisector and an altitude, i.e., the locus of points equidistant from the two lines (in the same way, the horizontal bisector is also a locus).
Now, the upper and left side angles are supplementary (let the measure of the upper be u, and the left, l)
The angle bisectors created 2 top-left angles, one with measure u/2, and the other, l/2
Obviously u/2+l/2=(u+l)/2
We know that u+l=180, so u/2+l/2=90.</p>
<p>Thus, we have 2 perpendicular lines.</p>
<p>yeah, it was “the locus of points that are equidistant from two intersecting lines.” Two things I don’t understand. What is a locus? (I think I can guess that from the answers, but a definition would be nice too) and how can a point be equidistant from two intersecting lines?</p>
<p>And where/how can I learn more about these types of questions?</p>
<p>locus=graph</p>
<p>we define the distance from a point to a line as the length of the line segment perpendicular to the line and containing the point.
so an equidistant point is a point with the distances being equal regarding the two different lines</p>
<p>ohhhhh I get it now… for some reason I was confusing myself by thinking it was in a 3D system:P</p>
<p>Clarinet: If you use Descartes’ Rule of Signs, you get that there’s 1 positive real solution and 0 negative real solutions, so there must be 2 non-real solutions.</p>
<p>how hard do u think this test was? u think a 44=800?</p>
<p>Yup, that’s right, Clarinet.</p>
<p>Rjcapr: I think it was about average. A 44 could probably go either way.</p>