<p>The distinct zeroes right? I got two.</p>
<p>I also remember a>0 and b=c and c doesn’t equal d for some function question</p>
<p>SAT. I got that too. It was the one where you had to interpret the graph. </p>
<p>And I got 2 distinct zeros for the maximum. ax^2+bx+c has a maximum of 2 distinct zeros when sqrt(b^2-4ac) is bigger than zero.</p>
<p>I had no idea how to do the function question that had the a,b,c, and d’s. What did you guys get for the one that had a circle and there was a line segment, r, and it asked u to find it in terms of sin? I think there was a question like this. Or I may be mixing things up lol</p>
<p>Ohh man I could have plotted the graph in my calculator and found the max and mins for the lake problem.</p>
<p>i got 1-cos(theata) because OR was cos theta and the big line was the radius of the circle</p>
<p>What was the 2 distinct zeroes question?</p>
<p>For the a + bi and a - bi question, I put the sum is real and the product was real - forgot the roman numeral answers think it was II and III</p>
<p>yeah i think i put the same thing ^</p>
<p>would -5 get you an 800? are the math 2 curves fairly consistent?</p>
<p>@cardyboy - I got 1 - cos(theta) , too :)</p>
<p>I tried plotting the lake question on the calculator but it wasn’t showing anything! :/</p>
<p>@SATnotACT - You’re right about the complex number question.</p>
<p>yes -5 is an 800</p>
<p>It gave us the number of students though. 40 kids. So it was between.</p>
<p>I got 1-cos(theta) because you had to subtract the x length away from the radius. </p>
<p>@HBound. I think 44 raw score is generally where the 800 cut off is. </p>
<p>and for the a+bi and a-bi question the product and sum were both real. (And @SAT, I think it was II and III as well). because if you apply the (x-a)(x+a)=x^2-a^2 rule. the product is a^2 - (-b^2) which is a real number</p>
<p>Do you guys remember the problem with the standard deviation? Like the weights were given and the std was 0.1 and then some stuff i forgot, what was the answer</p>
<p>For the one that said 2^n=4^m n and m are distinct integers between -4 and 4 or something like that I put 4, I saw someone else put 5. I think it could only be 5 if you say m and n are equal to 0 at the same time but I don’t think they can be</p>
<p>@Pyrohair adding to the weights does not affect standard deviation it was A. I believe .1</p>
<p>^ The standard deviation does not change. It is 0.1 itself.</p>
<p>@person. I put 5. 0 is an integer. (and I don’t remember it saying distinct at all. And I checked for that)</p>
<p>The standard deviation problem was .1 because they all raised 2 lbs so their shifts did not affect the standard deviation.</p>
<p>Yes ok, thats what i put</p>