@00barney the answer is 1/x
My calc teacher taught us that intersecting lines are defined as this: f(x1)>g(x1), f(x2)=g(x2), f(x3)<g(x3) with x1<x2<x3
This means that two circles do not intersect if they only touch at a point, they must also cross that point, or they are merely tangential. Can someone explain this to me??? It couldn’t be a point unless the spheres were tangential, not intersecting.
sigh sqrt(25-x^2) =y… Y^2= 25-x^2… X^2 + y^2 =25… It’s a circle with radius 5… Which is symmetric to the origin. How are you guys not seeing this…
@newCCuser12345 I dont mean to be rude, but why dont you just graph the square root thing? its not plus or minus the square root, that would be a circle. it was only the positive square root. how could Y have negative values when theres no negative in front of the square root? sqrt(25-x^2) is NOT equal to x^2+y^2= 25, the root would need plus or minus. You have yielded an extraneous root by squaring both sides, the explicitly defined function is undefined for negative Y values.
@Kylemcgrogan preach
did you guys get 10 for the minimum one? and -24 for the first one?
What did u get for f(x) < f(y)
@xxjmodxx was that the one with graphs? I think I put the only where it was continually increasing since as x increased, y increased
@WiscoPounce Thanks, do you also happen to remember if one of the answer choices was 12.9 or something? Because what I think I did wrong was I divided 31 by 60 instead of 60 by 31 and then screwed up from there. I’m hoping 12.9 wasn’t an option because I might’ve put that.
@didierdrogba I don’t remember the options, sorry.
@xxjmodxx it shouldve been the one that looked like an absolute value function. the v-shaped one in quads 1 and 2.
@newCCuser12345 sigh… didn’t you study the odd-even relations with symmetry? don’t mean to come off as rude, but like the previous guy said, the explicitly given is only symmetrical to the y-axis(hence an even function). functions that are odd (f(-x) = -f(x)) are symmetric across the origin.
@michelle426 the absolute value graph is incorrect. The question stated that f(xsub1) is less than or equal to f(xsub2) and xsub1 is less than or equal to xsub2, so the graph had to be continuely increasing. If you chose the absolute value graph, -3<1, but f(-3)>f(1)
@TheSATsSuck yep. exactly my reasoning.
@ypmagic i think for me, that graph was A or something. 6.44 was choice C.
@michelle426 it’s not the absolute value one as explained on the previous page. If -2 is less than -1 than the value for -2 was higher than -1 which is incorrect.
http://www.quora.com/Geometry/What-is-the-intersection-of-two-spheres-with-different-diameters i think i just found the answer to the sphere question… YAY I WAS RIGHT! IT IS A POINT AND A CIRCLE!
@schoolisfunforme yeah i read it wrong 
i think my score ranges from 740-780 at this rate. i might cancel?
@michelle426 I think if they are only toughing one another, then the surfaces are tangential, not intersecting.
@Kylemcgrogan I think they said the intersection of two spheres of different diameters