<p>yes catcat…</p>
<p>so radius is q, not -q… right…?</p>
<p>^^No, it asked for r in terms of q, but because the circle’s in quadrant two and since |r| = |q|, then r = -q.</p>
<p>What? I thought it said radius??</p>
<p>no dude, it wasn’t asking for radius, it was asking for the x value (r)…and since that it is in the 2nd quadrant, it is -q…</p>
<p>three questions -</p>
<ol>
<li><p>does anyone know the answer to the question about the frequencies and values…
i put 3, hopefully that was right…</p></li>
<li><p>anyone sure about the equidistant problem?
i put two parallel lines for that one…</p></li>
<li><p>for #41, the question about the set containing the values of x for x^2<4,
one of the answer choices was (-4,7)… so would that be the answer… or would it be (-3,3) like everyone else is saying?</p></li>
</ol>
<p>for the one about x Δ y= |x|-y^2 and it asked which statement is true, did anyone else put (-x)=x or something like that?</p>
<p>i agree with mkim, if (-3,3) was the answer, then (-4,7) would also work, and I remember that one being an answer choice i think</p>
<p>For the inequality question, I don’t think (-4,7) was a choice, but the only three answer choices I remember for sure are
(-3, 3)
(0,2)
(-1, 4)</p>
<p>Frequencies was four, I think.</p>
<p>mkim1124
The set of points equidistant from two intersecting lines is two perpendicular lines. The intersecting lines form four angles: two acute (vertical) ones and two obtuse (vertical) ones. The set of points equidistant from the two intersecting lines would be the angle bisector of the acute angles and the angle bisector of the two obtuse angles. The two angle bisectors intersect, so the can’t be parallel. They are, in fact, perpendicular.</p>
<p>In response to frequency being 4: Yep it was</p>
<p>I think I got 3 for the frequencies one. From what I remember, the table looked like:
score frequency
0 1
1 3
2 2
3 x
4 1
I want to try it again. Can anyone confirm I have the right table?</p>
<p>Not right. It was different, the 4 had the x by it and there was a 5.</p>
<p>Hubrid:
If the numbers went 1 to 5 instead of 0 to 4 (but the frequencies stayed the same), would it be right?</p>
<p>the right table was:
0 1
2 3
3 2
4 x
5 1</p>
<p>and the answer was 4…</p>
<p>Does anybody remember DEFINITELY seeing (-4,7)?</p>
<p>imaBOSS:
Thanks. I see it now: if x = 4, then the average would be 33/11 = 3, which is one of the scores. I see I stupidly put 3, since that’s the average, instead of the value of x, as I should have.</p>
<p>So the general consensus…</p>
<p>-(-3,3) -> although I put (0,2)
-2 perpendicular lines
-Frequency = 4
-Matrix = 2
-Probability = 7/15
-xyz plane = infinitely many perpendicular lines
-Two airplanes = 5.xx
-Intersecting curves = find x value</p>
<p>anybody put (0,z,0) for the answer to that one question?</p>