*The Official June 2012 Sat II Math Level 2 Thread*

<p>and how did you solve the lnx=e^-x problem?? I tried plugging it in my calc but it gave me a weird answer</p>

<p>@ozonik the lnx one was B, i think it was .27. I didnt even know how to do that, i just plugged them all in</p>

<p>You might have made the same mistike i made at first, it was asking what ln(x) was, not x</p>

<p>Do u remember if the negative was choice d?</p>

<p>wasn’t the lnx just 1? just graphing both, finding x value of intersection which was about 2.8, then taking the ln of that?</p>

<p>discuss the test here</p>

<p>[PiratePad:</a> OJFCkAIZVV](<a href=“http://piratepad.net/OJFCkAIZVV]PiratePad:”>http://piratepad.net/OJFCkAIZVV)</p>

<p>its like google docs</p>

<p>For the ln(x) problem, a subtracted ln(x) from both sides to get the equation e^(-x) - ln(x) = 0. Then I graphed that and found the x-intercept. The answer was B. Kind of cheap, but it worked.</p>

<p>oh and does this test penalize guessing? because i omitted a few, but im not sure if i should have guessed</p>

<p>^yeah there’s a penalty for guessing, but if you can eliminate at least one answer, it works in your favor to guess.</p>

<p>Does anyone remmeber what choice was -1/pi?</p>

<p>It said an ERROR of .05 degrees. this means you ADD that onto to the .0024 degrees you get by doing inverse tangent. this gives you </p>

<p>tan(.0524 degrees) = (x/1188000)</p>

<p>x is the new distance that the laser would be pointing from the center.
x = 1086.5 ft.
then you subtract the 50. </p>

<p>1036.5 is YOUR ANSWER</p>

<p>WHATS MY NAME</p>

<p>@magentaturtle
That was an actual answer and that was the right one</p>

<p>@idontgive
That is right!!</p>

<p>[Sync.in:</a> ktLw9y4uyW](<a href=“http://sync.in/ktLw9y4uyW]Sync.in:”>http://sync.in/ktLw9y4uyW)</p>

<p>since the other link is full</p>

<p>What did you guys get for the one with how many segments can be formed from the points given. </p>

<p>I put 10 which was (C)</p>

<p>10 is right. The possibilities were 4+3+2+1.</p>

<p>were does the .0024 come from? i thought it was just pointing at the center so u use tangent(0.05)</p>

<p>@Idontgive – I don’t think that’s right. You just have to use .05 degrees as the angle on the ground, and then use tangent to find the laser’s distance from the center of the disk. Then subtract 50.</p>

<p>you find the initial degree measure.</p>

<p>one leg of the triangle is 50ft and the other is 225 miles ( 1188000 ft)
you use these to find the angle measure of the smallest angle which comes out as .0024 degreess]</p>

<p>I was scoring like 730 on practice tests, pretty confident I got above a 750… Very easy.</p>

<p>No - the laser isn’t initially pointing at the edge of the disk, it’s pointing at the center. There’s an initial angle of 0 degrees from perpendicular.</p>